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blagie [28]
3 years ago
14

How to solve (s + 5)(s - 5)

Mathematics
2 answers:
Bas_tet [7]3 years ago
4 0

Answer:s^2-25

Step-by-step explanation:

meriva3 years ago
4 0

Answer:

you would have to multiply so,

s*s is s^2

s*-5 is -5s

s*5 is 5s

5*-5 is -25

the final answer would be s^2-25 (-5s and 5s cancel each other out)

hope this helped!!

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For which interval is the average rate of change of f(x) negative?
HACTEHA [7]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ
atroni [7]

Answer: y=Ce^(^3^t^{^9}^)

Step-by-step explanation:

Beginning with the first differential equation:

\frac{dy}{dt} =27t^8y

This differential equation is denoted as a separable differential equation due to us having the ability to separate the variables. Divide both sides by 'y' to get:

\frac{1}{y} \frac{dy}{dt} =27t^8

Multiply both sides by 'dt' to get:

\frac{1}{y}dy =27t^8dt

Integrate both sides. Both sides will produce an integration constant, but I will merge them together into a single integration constant on the right side:

\int\limits {\frac{1}{y} } \, dy=\int\limits {27t^8} \, dt

ln(y)=27(\frac{1}{9} t^9)+C

ln(y)=3t^9+C

We want to cancel the natural log in order to isolate our function 'y'. We can do this by using 'e' since it is the inverse of the natural log:

e^l^n^(^y^)=e^(^3^t^{^9} ^+^C^)

y=e^(^3^t^{^9} ^+^C^)

We can take out the 'C' of the exponential using a rule of exponents. Addition in an exponent can be broken up into a product of their bases:

y=e^(^3^t^{^9}^)e^C

The term e^C is just another constant, so with impunity, I can absorb everything into a single constant:

y=Ce^(^3^t^{^9}^)

To check the answer by differentiation, you require the chain rule. Differentiating an exponential gives back the exponential, but you must multiply by the derivative of the inside. We get:

\frac{d}{dx} (y)=\frac{d}{dx}(Ce^(^3^t^{^9}^))

\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*\frac{d}{dx}(3t^9)

\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*27t^8

Now check if the derivative equals the right side of the original differential equation:

(Ce^(^3^t^{^9}^))*27t^8=27t^8*y(t)

Ce^(^3^t^{^9}^)*27t^8=27t^8*Ce^(^3^t^{^9}^)

QED

I unfortunately do not have enough room for your second question. It is the exact same type of differential equation as the one solved above. The only difference is the fractional exponent, which would make the problem slightly more involved. If you ask your second question again on a different problem, I'd be glad to help you solve it.

7 0
2 years ago
What is the measure of W the parallelogram shown?
nexus9112 [7]

Answer:

148 degrees

Step-by-step explanation:

For a parallelogram, angles on the same side sum up to be 180

what this simply means is that they are supplementary

Mathematically, we have it that;

X + W = 180

W = 180 - X

W = 180 -32

W = 148 degree

6 0
3 years ago
Every winter I fly home to Michigan it takes five hours what is my average speed
nignag [31]
Well you did not say how many miles you are from Michigan
6 0
3 years ago
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What is the value of b in the equation 2x-y=6
andriy [413]

Answer:

are you sure its b? b doesnt seem to be present in 2x-y=6

4 0
3 years ago
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