Given:
Two jugs are similar. The smaller jug has radius 4 cm and the bigger jug has radius 6 cm and surface area 125 cm².
To find:
The area of the smaller jug.
Solution:
If two figures are similar, then the ratio of their areas is proportional to the square of the corresponding sides of the figures.
Two jugs are similar. So,
Therefore, the area of the smaller jug is about 55.56 cm².
Answer:
Aditya evaluates the numerator of the expression when x = –1. He finds the remainder of the division to be –1
Step-by-step explanation:
– 12x¹⁷+ 3x⁵ – 9x² – 1 / x + 1
To obtain the answer to question, let us apply the remainder theorem. This is illustrated below:
Assume:
x + 1 = 0
Subtract 1 from both side
x + 1 – 1 = 0 – 1
x = – 1
Next, we shall substitute the value of x into – 12x¹⁷+ 3x⁵ – 9x² – 1. This is illustrated below:
– 12x¹⁷+ 3x⁵ – 9x² – 1
x = – 1
– 12(–1)¹⁷+ 3(–1)⁵ – 9(–1)² – 1
– 12(–1) + 3(–1) – 9(1) – 1
12 – 3 – 9 – 1
= –1
Thus, using the remainder theorem,
– 12x¹⁷+ 3x⁵ – 9x² – 1 / x + 1 will result to –1
She will need to sell 18 necklaces a month to reach 1650
Answer:
That is an obtuse isosceles
