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aleksley [76]
3 years ago
12

Can someone help please

Mathematics
1 answer:
Sophie [7]3 years ago
7 0

Answer:

33

Step-by-step explanation:

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A building is 1450ft tall. How many meters tall is the building ? Use the fact that 1m = 3.28ft
Mamont248 [21]

Answer:

441.96

Step-by-step explanation: divide 1450 by 3.28

5 0
3 years ago
What are the first four terms if the sequence represented by the expression n (n-1) -4?
shepuryov [24]
We have that
<span>n (n-1) -4

for n=1
a1=1*(1-1)-4------> a1=-4

for n=2
</span>a2=2*(2-1)-4------> a2=-2

for n=3
a3=3*(3-1)-4------> a3=2

for n=4
a4=4*(4-1)-4------> a4=8

the answer is
-4,-2, 2, 8
5 0
3 years ago
Miss Kirkland Works 40 hours on Mondays in 8 hours on Tuesdays in the school library during one week in May she worked 1/4 of he
Rashid [163]

Answer:

She worked 12 hours for the week

Step-by-step explanation:

Given that :

Hours worked :

Mondays = 40 hours

Tuesdays = 8 hours

If 1/4 of regular hours was worked in a certain week, the number of hours worked that week can be calculated thus ;

1/4 (Monday hours + Tuesday hours)

1/4(40 + 8)

(1/4 * 40) + (1/4 * 8)

10 + 2

= 12 hours

8 0
3 years ago
find the equations of the tangents to the curve y= x(x-1)(x+2) at the points where the curve cuts the x axis
antoniya [11.8K]

First of all, we compute the points of interest, i.e. the points where the curve cuts the x axis: since the expression is already factored, we have

x(x-1)(x+2) = 0 \iff x=0\ \lor\ x-1=0\ \lor\ x+2=0

Which means that the roots are

x=0\ \lor\ x=1\ \lor\ x=-2

Next, we can expand the function definition:

y = x(x-1)(x+2) = x^3 + x^2 - 2x

In this form, it is much easier to compute the derivative:

y' = 3x^2+2x-2

If we evaluate the derivative in the points of interest, we have

y'(-2) = 6,\quad y'(0)=-2,\quad y'(1)=3

This means that we are looking for the equations of three lines, of which we know a point and the slope. The equation

y-y_0=m(x-x_0)

is what we need. The three lines are:

y-0=6(x+2) \iff y = 6x+12  This is the tangent at x = -2

y-0=-2(x-0) \iff y = -2x  This is the tangent at x = 0

y-0=3(x-1) \iff y = 3x-3  This is the tangent at x = 1

7 0
3 years ago
Explain in words how to use the side lengths of a triangle to determine if the triangle is a right, acute, or obtuse triangle.
RUDIKE [14]

basically write the triangle in degree language like this is a acute angle because this is a 70* degree angle and talk more

8 0
3 years ago
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