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Makovka662 [10]
3 years ago
13

A collection of 33 coins having dimes quarters and nickels, there are 3 times more nickels then dimes and half the amount of dim

es as nickels, all of the coins equal $3.30 how many of each coin?
Mathematics
1 answer:
zloy xaker [14]3 years ago
3 0

Answer:

Each coins are quarters of <u>6</u>, nickels of <u>18</u> and the dimes of <u>9</u>.

Step-by-step explanation:

<u><em>There is a mistake in question.</em></u>

The question must be:

A collection of 33 coins having dimes quarters and nickels, <u>there are 3 times as many nickels as quarters, and one-half as many dimes as nickels</u>, all of the coins equal $3.30 how many coins of each kind are there?

Now, to find the number coins of each.

Let the quarters be x.

Nickels be 3x.

And the dimes be \frac{3x}{2}.

So, the total collection of coins are:

x+3x+\frac{3x}{2} =33.

On adding the fractions we get:

\frac{2x+6x+3x}{2} =33

\frac{11x}{2} =33

Multiplying both sides by 2 we get:

11x=66

Dividing both sides by 11 we get:

x=6.

Thus, quarters = 6.

Nickels = 3x=3\times 6=18.

Dimes = \frac{3x}{2} =\frac{3\times 6}{2} =\frac{18}{2}=9 .

Therefore, each coins are quarters of 6, nickels of 18 and the dimes of 9.

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