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Inessa [10]
3 years ago
9

2. A line goes through the points (4, 5) and (2, -6). Write the equation of the line in slope-intercept form. Show your work for

full credit. (How did you go from those two points to having the equation in slope-intercept form? Or, how did you go form having the equation in point-slope form [above in #1] to slope- intercept form?). Do not draw graphs, I want you to complete this problem algebraically (Using numbers, variables, and/or symbols). Circle your answer. (4 points)
Mathematics
1 answer:
kipiarov [429]3 years ago
5 0

Answer:

y = 5.5x - 17

Step-by-step explanation:

(4,5)(2,-6)

  • M = ∆y/∆x
  • -6-5/2-4
  • -11/-2 this is the gradient
  • chose any of the point then introduce another point
  • (4,5) (x,y) the gradient is -11/-2
  • M =∆y/∆x
  • y-5/x-4 = -11/-2
  • -2(y-5) = -11 ( x -4)
  • -2Y + 10 = -11x + 44
  • -2Y = -11x + 44 -10
  • -2Y = -11x + 34
  • divide the while equation by -2
  • y = 5.5x + - 17
  • y= 5.5x - 17
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What is the slope of the line that passes through the points (2, 2), and (4,2)​
vfiekz [6]

Answer:

There is no slope. m=0

Step-by-step explanation:

m=\frac{rise}{run}=\frac{2-2}{4-2}=\frac{0}{2}=0

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MatroZZZ [7]

Answer:

You have the formula wrong.

The volume of a cylinder = PI * radius^2 * height

To find the height, the formula is:

height = volume / (PI*radius^2)

I'm assuming the radius = .6 meters so

height = 720 / (3.14159265 * .6^2)

height = 720 / 1.130973354

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Step-by-step explanation:

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3 years ago
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tankabanditka [31]
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Ira Lisetskai [31]

Answer:

Option (b) is correct.

The sum of given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y} is  2xy\sqrt{y}+2xy^2\sqrt{x}

Step-by-step explanation:

Given:Expression \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

We have to find the sum of the given expression and choose the correct from the given options.

Consider the given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}.

\sqrt{x^2y^3} can be written as \sqrt{x^2y^2y}=xy\sqrt{y}

Also, 2\sqrt{x^3y^4} can be written as 2\sqrt{x^3y^4}=2\sqrt{x^2x(y^2)^2}=2xy^2\sqrt{x}

Now, the given expression becomes,

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}.

Now, adding like term, terms having same variable with same degree.

=2xy\sqrt{y}+2xy^2\sqrt{x}.

Thus, The sum of given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y} is  2xy\sqrt{y}+2xy^2\sqrt{x}

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