Question

The coordinates of the vertices of a rectangle are (-8,2),(0,4),(1,0), and (-7,-2)

Answer 1

Answer:

Perimeter of rectangle =24.7 units

Step-by-step explanation:

From the figure, Perimeter of the rectangle=$2(length+breadth)$

=$2(BC+CD)$

Now, BC=$\sqrt{(0-1)^{2}+(4-0)^{2}}=\sqrt{1+16}=\sqrt{17}=4.1 units$

and CD=$\sqrt{(1+7)^{2}+(0+2)^{2}}=\sqrt{64+4}=\sqrt{68}=8.2 units$

Therefore,perimeter of the rectangle= $2(4.1+8.2)=2(12.3)=24.7 units$.

Answer 2

Answer:

Perimeter of rectangle is 24.74 squnits.

Step-by-step explanation:

Given The coordinates of the vertices of a rectangle are (-8,2),(0,4),(1,0), and (-7,-2). we have to find the perimeter of rectangle.

As we know,

Perimeter of rectangle=2(L+B)

Length of rectangle=$\sqrt{(0+8)^2+(4-2)^2}=\sqrt64+4=\sqrt68=2\sqrt17$

Breadth of rectangle=$\sqrt{(1-0)^2+(0-4)^2}=\sqrt1+16=\sqrt17$

Now, Perimeter=$2(2\sqrt17+\sqrt17)$

                        = $2(3\sqrt17)=6\sqrt17units=24.74 squnits$