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serious [3.7K]
3 years ago
7

a computer store bought a program at a cost of $20 and sold it at a selling price$26. what is the percent markup

Mathematics
1 answer:
tekilochka [14]3 years ago
8 0

it would be a 6 percent mark up :)

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13. Mis the midpoint of PR, PM = 2x + 5, and MR = 4x – 7. Solve for x and find PR.
enyata [817]

Add 2x + 5 and 4x - 7

Then you isolate the variable or “get rid of” the numbers that re stopping you from getting “x”.

By doing the inverse operation.

If you add ___ you subtract ____ it form itself

If you subtract ___ you add ____ To itself.

So you Cancel out by getting rid of the other numbers.

Same thing with multiplying and dividing.

If you multiply ____ you divide___ but don’t divide “x”

Only the integer.

If you divide _____ you multiply ____ it

8 0
3 years ago
Please help me find the slope thank u
Rzqust [24]
Y2-Y1
Over X2-X1 and then there is your slode
6 0
3 years ago
Does anybody know the answer to these questions?
san4es73 [151]

Answer:

  1. 625,000 J

  2. 100 J

  4. 5 kg

  5. √5 ≈ 2.236 m/s

Step-by-step explanation:

You should be aware that the SI derived units of Joules are equivalent to kg·m²/s².

To reduce confusion between <em>m</em> for mass and m for meters, we'll use an <em>italic m</em> for mass.

In each case, the "find" variable is what's left after we put the numbers into the formula. It is what the question is asking for. The "given" values are the ones in the problem statement and are the values we put into the formula. The formula is the same in every case.

__

1. KE = (1/2)<em>m</em>v² = (1/2)(2000 kg)(25 m/s)² = 625,000 kg·m²/s² = 625,000 J

__

2. KE = (1/2)<em>m</em>v² = (1/2)(0.5 kg)(20 m/s)² = 100 kg·m²/s² = 100 J

__

4. KE = (1/2)<em>m</em>v²

  250 J = (1/2)<em>m</em>(10 m/s)² = 50 m²/s²

  (250 kg·m²/s²)/(50 m²/s²) = <em>m</em> = 5 kg

__

5. KE = (1/2)<em>m</em>v²

  2000 kg·m²/s² = (1/2)(800 kg)v²

  (2000 kg·m²/s²)/(400 kg) = v² = 5 m²/s²

  v = √5 m/s ≈ 2.236 m/s

7 0
3 years ago
Plz answer it all in order
igomit [66]

Answer:

1.0.667

2.3.5,0.12,0.680

3.0.2,0.40,0.112

4.2.5,0.57,1.222

5.1.2,0.75,0.071

6.7.5,0.03,

3 0
3 years ago
In triangle ABC, c is the hypotenuse, 0=25°, and b =3, Find the length of c ?
Charra [1.4K]

Answer:

\large\boxed{c\approx3.31}

Step-by-step explanation:

Use cosine:

cosine=\dfrac{adjacent}{hypotenuse}

\cos\theta=\dfrac{b}{c}

We have:

\theta=25^o\to\cos25^o\approx0.9063\\\\b=3

Substitute:

\dfrac{3}{c}=0.9063

\dfrac{3}{c}=\dfrac{9063}{10000}          <em>cross multiply</em>

9063c=30000          <em>divide both sides by 9063</em>

c\approx3.31

8 0
3 years ago
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