Answer:
Step-by-step explanation:
50.
line AB that has the points (2,5) and (9,2) hhas the slope
m= (y2-y1) / (x2-x1)= 5-2 / 2-9 = 3/-7 = -3/7
Parallel line have the same slope so m= -3/7 for the line that has the point (-3,4).
Point-slope equation is y-y1 = m (x-x1), y -4 = -3/4 (x+3) or
you can writte it as y= (-3/4)x - 9/4 +16/4 so y = (-3/4)x + 7/4
51.
line PQ has slope m= -6+1 / 4-6 = -5/-2 = 5/2
Perpendicular lines have their slope negative reciprocal of eachother so the line that goes trough the point (1,3) has the slope m= -2/5
y-3 = -2/5 (x-1)
Answer:
2
Step-by-step explanation:
Yeah its 2 I can explain but will be long but if want comment and I will post but most likely its 2
Answer:
for example, if f(x)= x^2 + 3
and they gave write f(5)= 5^2 +3
=25+3=28
Answer:
T = 59
U = 27
V = 94
Step-by-step explanation:
(5x +4) + (8x + 6) + (2x+5) = 180
15x + 15 = 180
15x = 165
x = 11