<u>Answer-</u>
<em>The height of the prism is</em><em> 6 units</em>
<u>Solution-</u>
As the base of the prism is a hexagon consisting of 2 congruent isosceles trapezoids.
So,

And,

Also,


Putting all the values,

As the volume is given, so


Answer:
11, 13 and 15.
Step-by-step explanation:
Let's say that the odd number is "x". If x is for example 15, then the next ODD number would be 15+2=17 and the one after that would be 15+2+2=15+4=19.
Applying that here, we get:
Odd number* the next odd number*the next odd number=2145
x*(x+2)*(x+4)=2145
x*(x^2+4x+2x+8)=2145
x^3+6x^2+8x=2145
By solving the polynomial, you get x=11.
Which makes our three numbers: 11, 13 and 15.
11*13*15=2145. The answer checks.
Answer:
92°
Step-by-step explanation:
We can say that the angle that is of x degrees is an inscribed angle because its vertex is on the circle and its sides are made up of rays. When you have an inscribes angle, it measures exactly half the angle it intercepts. In this case that angle is 184°. So, because of this we can say:
x = 184° / 2
x = 92°
If you've started pre-calculus, then you know that the derivative of h(t)
is zero where h(t) is maximum.
The derivative is h'(t) = -32 t + 96 .
At the maximum ... h'(t) = 0
32 t = 96 sec
t = 3 sec .
___________________________________________
If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.
In that case, the question GIVES you the maximum height.
Just write it in place of h(t), then solve the quadratic equation
and find out what 't' must be at that height.
150 ft = -16 t² + 96 t + 6
Subtract 150ft from each side: -16t² + 96t - 144 = 0 .
Before you attack that, you can divide each side by -16,
making it a lot easier to handle:
t² - 6t + 9 = 0
I'm sure you can run with that equation now and solve it.
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.
(Funny how the two widely different methods lead to the same answer.)
The answer is from AL2006