

The least power of 2 that exceeds 25 is

, so we have

- - -

The least integer

that satisfies this inequality would clearly be

.
Answer:
1- 3(BDE)
2- 37.18 (83.36 - 46.18=64)
3- 64 (83.36 - 19.36)
4- 140.2 (56.84 + 83.36=140.2)
Alright, so if the first number is x, the second number is y, and the third number is z, we have x+y+z=270. Next, since we know that x=y-1 since it is less than y by one and z=y+1, we have y-1+y+y+1=y+y+y=3y=270. Dividing both sides by 3, we get y=90