Question

Maya, Ahmad, and Joe served a total of 75 orders Monday at the school cafeteria. Joe served 2 times as many orders as Maya. Ahmad served 5 fewer orders
than Maya. How many orders did they each serve?

Answer 1

Total number of orders served by Maya, Ahmad and Joe on Moday = 75

Let the number of orders Maya served be x.

Then :

Number of orders Joe served = 2x

Number of orders Ahmad served = x - 5

This can be written in an equation as :

$\tt \: 2x + x - 5 + x = 75$

$= \tt 4x - 5 = 75$

$= \tt 4x = 75 + 5$

$= \tt 4x = 80$

$= \tt \: x = \frac{80}{4}$

$= \tt \: x = 20$

Which means :

Number of orders Joe served :

= 2 × 20

= 40

Thus, Joe served 40 orders.

Number of orders Maya served = 20

Number of orders Ahmad served :

= 20 - 5

= 15

Thus, Ahmad served 15 orders.

Therefore,

• Maya served 20 orders
• Ahmad served 15 orders
• Joe served 40 orders.