Food A has fewer calories per serving.
I found this by taking the first food (A) and dividing 150 by 3. This gave me 50, which I added onto 150 to give me my 4/4 of a serving (200 calories).
With food B, I did the same process. I took 250/2 and added that to the original amount to get the final third of the serving, which resulted in food B being 375 calories.
<span>To evaluate the given expression, we need the values of each variable and substitute these values to the expression. Then, go on with the operations involved.
</span>4x - y - 2z
4(-2) - (3) - 2(-2)
-8 - 3 + 4
-7
I think it’s the number 3 I’m not sure I’m learning this stuff rn I’m getting the hang of it just it’s hard and not hard at the same time
