Let G be some point on the diagonal line away from point E.
Angle DEG represents angle 1.
We're given that angle DEF is a right angle which means it's 90 degrees. Angle DEG is some angle smaller than 90 degrees. By definition, that must mean angle 1 is acute. Any acute angle is smaller than 90 degrees. There's not much else to say other than this is just a definition problem.
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Extra side notes:
If angle 1 was a right angle, then that would mean angle GEF would have to be 0 degrees; however the diagram shows this isn't the case.
If angle 1 was obtuse, then there's no way we'd be able to fit it into angle DEF. In other words, there's no way to have an angle larger than 90 fit in a 90 degree angle.
Answer:
768
Step-by-step explanation:
because 50 percent of the num is 96 you double that and then multiply by four
Answer:
![\left( fg\right) \left( x\right) =2x^3\sqrt[3]{x}\\\\\left( \frac{f}{g} \right) \left( x\right) =\frac{2x^{3}}{\sqrt[3]{x} }](https://tex.z-dn.net/?f=%5Cleft%28%20fg%5Cright%29%20%20%5Cleft%28%20x%5Cright%29%20%20%3D2x%5E3%5Csqrt%5B3%5D%7Bx%7D%5C%5C%5C%5C%5Cleft%28%20%5Cfrac%7Bf%7D%7Bg%7D%20%5Cright%29%20%20%5Cleft%28%20x%5Cright%29%20%20%3D%5Cfrac%7B2x%5E%7B3%7D%7D%7B%5Csqrt%5B3%5D%7Bx%7D%20%7D)
Step-by-step explanation:
D I had to learn about this for an entire quarter
