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Dovator [93]
3 years ago
14

What is the best approximation for the cube root of 9.32

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
5 0
2.1 or 2. Hopefully this is right.
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Compute the following products.<br> (4x+5)(4x−5)<br><br> (4x+5)2
bearhunter [10]
(4x+5)(4x-5) is equal to 16x^2+20x-20x-25
The positive and negative 20x cancel out
Leaving you with: 16x^2 - 25
[S/N this is a pattern that shows up a decent amount. Whenever you have something that looks like (x^2-y^2) it factors out to (x+y)(x-y). It might be helpful to remember]

The next one, (4x+5)2, just follows the distributive property. Multiply both components within the parentheses bye the coefficient of 2: 8x+10
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3 years ago
100 BRAINLY POINTS!!!!!!
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THE FLAT FEE OF $60 WOULD BE THE Y INTERCEPT BECAUSE THE $5 IS A RATE OF CHANGE DEPENDENT ON THE AMOUNT OF GIGABYTES THE PERSON USES.
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2 years ago
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Answer this question, thx for the help <br> (the 4th one is this shape O )
RideAnS [48]

Answer:

1st one

Step-by-step explanation:

5 0
3 years ago
ACTIVITY 2 (19) Mr Duma recently inherited a rectangular plot, part of the estate left by his late father. The plot with the fol
seraphim [82]

The sum of the lengths of three sides of the rectangle, gives the length

of the fencing, while one third of the rectangle area is for the pavement.

Responses:

Project A: The formula for the length of the fencing is, L = 4·x - 1

Project B: Length of the fancy wall = 2·x + 1

Project \ C:Area \ of \ the \ paving = \underline{ \dfrac{2\cdot x^2 }{3} - \dfrac{x }{3}  - \dfrac{1}{3}}

<h3>Which method can be used to find the length and area of paving from the given equations?</h3>

Project A: Let QP and SR represent the longest sides of the rectangle, we have;

PQ = SR = 2·x + 1

Given parameters are;

Length of the rectangular plot = 2·x + 1

Width of the rectangular plot = x - 1

Vertices of the rectangular plot are; QPSR

Project A: Let QP and SR represent the longest sides of the rectangle, we have;

PQ = SR = 2·x + 1

Which gives;

SP = QR = x - 1

The length of the fencing, L = SP + PQ + QR = x - 1 + 2·x + 1 + x - 1 = 4·x - 1

  • The formula for the length of the fencing is, L =<u> 4·x - 1</u>

Project B: The front side is SR

Therefore;

  • Length of the fancy wall = <u>2·x + 1</u>

Project C:

Area, A = Length × Width

Area of the plot, A = (2·x + 1) × (x - 1) = 2·x² - x - 1

  • Area \ of \ the \ paving = \dfrac{1}{3} \times \left(2 \cdot x^2 - x - 1\right) = \underline{ \dfrac{2\cdot x^2 }{3} - \dfrac{x }{3}  - \dfrac{1}{3}}

Learn more about writing equations here:

brainly.com/question/24760633

6 0
2 years ago
C=prn is formula for calculating total ?
boyakko [2]

Answer:

for calculating commissions


Step-by-step explanation:


6 0
3 years ago
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