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VashaNatasha [74]
3 years ago
14

One-way Analysis of Variance uses a F test to compare the variance between the treatment level means to the error variance (the

pooled variance within levels). For this test, one assumption is that the observations are random samples drawn from normally distributed populations with unequal variances.TrueFalse
Mathematics
1 answer:
vagabundo [1.1K]3 years ago
5 0

Answer:

False

Step-by-step explanation:

The assumption of ANOVA are:

1)  the k- samples are selected randomly and independently from the respective populations

2) All the k population from which samples are drawn are normally distributed with means u1,u2, u3,........

3) the observations are random samples drawn from normally distributed populations with equal variances. The technical term for this assumption is <u><em>Homoscedasticity.</em></u>

<u><em></em></u>

<u><em>Failure of any assumption will impair the technique. However, minor deviations can be tolerated. Sometimes square roots and logs are used to make assumptions true.</em></u>

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One-Half of a number increased by 6 is less than 34
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Answer: ½ x + 6 < 34 ; x < 56

Step-by-step explanation:

  1. Subtract 6 on both sides. ½ x < 28.
  2. Divide ½ on both sides. x < 56.
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Problem Page A table of values of a linear function is shown below. x −1 0 1 2 3 y −6 −8 −10 −12 −14 Find the slope and y -inter
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.. y = -2x -8
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If frys cost 3.24 money per pound at a gas station and I buy 3.5pounds how much money was I spent
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Read 2 more answers
Imagine a deck of 500 cards numbered from 1 to 500. If all the cards are shuffled randomly and you are asked to pick three cards
amm1812

Answer:

P = 1 / 6

Step-by-step explanation:

Given:-

- A deck has 500 cards

- Numbered from 1-500

Find:-

you are asked to pick three cards, one at a time, what's the probability of each subsequent card being larger than the previous drawn card

Solution:-

- Suppose we draw three cards. We don't care what they actually are, irrespective of number.

- Let the three numbers be a, b, c: Such that:

                                       a < b < c.

- The total possible combinations with 3 numbered cards will be:

                                       a b c

                                       b a c

                                       a c b

                                       b a c

                                       b c a

                                       c a b

- We have 6 possibilities for 3 numbered cards. So the probability of  of each subsequent card being larger than the previous drawn card would be:

                                     P = 1 / possible combinations

                                    P = 1 / 6

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3 years ago
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