Tossing a die will have 6 possible outcomes. Those are having sides that are number 1 to 6. The sample space of tossing 3 dice is equal to 6³ which is equal to 216. Now for the calculation of probabilities,
P(two 5s) = (1 x 1 x 5)/216
As we have to have the 5 in the die for two times, then for the 1 time, we can have all other numbers except 5. The answer is 5/216.
P(three 5s) = (1 x 1 x 1)/216 = 1/216
P(one 5 or two 5s) = (1 x 5 x 5)/216 + (1 x 1 x 5)/216 = 5/36
Answer:
The y-intercept is the point (0,-8)
see the attached figure
Step-by-step explanation:
we have

we know that
The y-intercept is the value of the function f(x) when the value of x is equal to zero
so
For x=0

therefore
The y-intercept is the point (0,-8)
see the attached figure to better understand the problem
Answer: $15
Step-by-step explanation:
-$50 + $75 = $15
Answer:
a₃₅ = 182
Step-by-step explanation:
There is a common difference d between consecutive terms, that is
d = 17 - 12 = 22 - 17 = 5
This indicates the sequence is arithmetic with n th term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 12 and d = 5 , then
a₃₅ = 12 + (34 × 5) = 12 + 170 = 182