Answer: Last Option
![4x^5\sqrt[3]{3x}](https://tex.z-dn.net/?f=4x%5E5%5Csqrt%5B3%5D%7B3x%7D)
Step-by-step explanation:
To make the product of these expressions you must use the property of multiplication of roots:
![\sqrt[n]{x^m}*\sqrt[n]{x^b} = \sqrt[n]{x^{m+b}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Em%7D%2A%5Csqrt%5Bn%5D%7Bx%5Eb%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%5E%7Bm%2Bb%7D%7D)
we also know that:
![\sqrt[3]{x^3} = x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%20%3D%20x)
So
![\sqrt[3]{16x^7}*\sqrt[3]{12x^9}\\\\\sqrt[3]{16x^3x^3x}*\sqrt[3]{12(x^3)^3}\\\\x^2\sqrt[3]{16x}*x^3\sqrt[3]{12}\\\\x^5\sqrt[3]{16x*12}\\\\x^5\sqrt[3]{2^4x*2^2*3}\\\\x^5\sqrt[3]{2^6x*3}\\\\4x^5\sqrt[3]{3x}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B16x%5E7%7D%2A%5Csqrt%5B3%5D%7B12x%5E9%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B16x%5E3x%5E3x%7D%2A%5Csqrt%5B3%5D%7B12%28x%5E3%29%5E3%7D%5C%5C%5C%5Cx%5E2%5Csqrt%5B3%5D%7B16x%7D%2Ax%5E3%5Csqrt%5B3%5D%7B12%7D%5C%5C%5C%5Cx%5E5%5Csqrt%5B3%5D%7B16x%2A12%7D%5C%5C%5C%5Cx%5E5%5Csqrt%5B3%5D%7B2%5E4x%2A2%5E2%2A3%7D%5C%5C%5C%5Cx%5E5%5Csqrt%5B3%5D%7B2%5E6x%2A3%7D%5C%5C%5C%5C4x%5E5%5Csqrt%5B3%5D%7B3x%7D)
Answer:
x=−4+√22 or x=−4−√22
Step-by-step explanation:
Substitute all values in the quadratic formula.
Solve.
Answer: D) 18
======================================================
Explanation:
|-11| simplifies to 11
|-7| simplifies to 7
Whatever is inside the absolute value, you just remove the negative and that's the result of that absolute value expression. It represents the distance on a number line. So for instance -11 is 11 units from 0, which is why |-11| = 11.
Overall,
|-11| + |-7| = 11 + 7 = 18
So we know that the bag has total 15 cookies, and 1 cookie that does not have any raisin. Finally, the probability that one cookie won't have any raisin is 1/15 or 7 percent. Hope it help!
4 seconds, so whatever the letter is for the answer I have provided, select it
