The answer is 46.125 hope this helped :)
The axis of symmetry for this parabola is the x-axis. The general form of the equation is:
4p(x-h) = (y-k)^2
where the focus has the coordinates of (h+p,k)
Manipulating the given equation to the general form:
4(1/3)(x-7)^2 = (y - 0)^2
Therefore the coordinates of the focus is:
(7+(1/3),0)
The answer is A.) (71/3,0)
If he hits the target 95% of the time, then you could say that he has a probability of 0.95, or 95% of hitting the target. Let p = the probability of hitting the target or p = 0.95. So you are interested that he misses the target at least once - this could be thought of as not getting a perfect score. So to get a perfect score, it is 0.95 for each target -- 0.95^15 for 15 targets is 0.464. Thus to miss at least one target he needs to NOT have a perfect score -- 1 - 0.464 = 0.536, or 53.6% of happening. Enjoy
I have to say a because the problem is continuing
