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miss Akunina [59]
3 years ago
11

Verbal expression of y over 4 minus 7

Mathematics
1 answer:
skad [1K]3 years ago
8 0
Y/4 - 7 = y is 28.

So basically y = 28.
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N2 +21n + 20 factor​
liq [111]

Answer:

(x+1)(x+20)

Step-by-step explanation:

1) find two factors of 20 that sum up to 21.

2) 1 and 20 are two facts of 20 that sum up to 21.

5 0
3 years ago
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Is this correct or wrong?​
aliina [53]

Answer:

  close. Quotient = x² -8x +27; Remainder -77

Step-by-step explanation:

It looks like you forgot an x in your restatement of the quotient. Otherwise the work appears correct.

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  x² -8x +27 -77/(x+3)

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3 0
3 years ago
An angle is drawn in standard position passing through the unit circle at (0.643,0.766). The angle in standard position θ has a
Flura [38]
<h2>Hello!</h2>

The asnwer is: Cos50° ≈ 0.643

<h2>Why?</h2>

A unit circle is a cirgle with a radius equal of 1, knowing that,  also know the following:

The angle is drawn passing trough the unit circle at (0.643,0.766) it means that:

x=0.643\\y=0.766

So,

Cos50° ≈ 0.643

We can prove that by following the next steps:

- If it's a unit circle,here is a right triangle with hypotenuse of 1,

1^{2}=x^{2}+y^{2}

1^{2}=0.643^{2}+0.766^{2}

1^{2}=0.4134 +0.5867

1=1.0001=1

- We can determine the cosine of the angle by the following formula:

cos(\alpha)=\frac{x}{hypotenuse} \\cos(\alpha)^{-1}=cos(\frac{0.643}{1})^{-1} \\\alpha=49.98

Therefore,

Cos(α)=49.98°≈50°

Also, if there is a right triangle, according to the Pythagorean Thorem:

1^{2}=(Cos(\alpha))^{2}+(Sin(\alpha))^{2} \\Cos(50)=\sqrt{1-(Sin(50))^{2}}=0.6427

Hence,

Cos50° ≈ 0.643

Have a nice day!

3 0
3 years ago
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[(b+3)÷(a–2)](−4) if a=−5, b=6.
finlep [7]
9/-7 x -4=

36/7

Hope it helps
6 0
3 years ago
Plzzz help???????????
uysha [10]

Answer:

Its either C. or D.  

Step-by-step explanation:

6 0
3 years ago
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