The terms in which value of x when substituted leaves final value of p(x) = "0".
Here, x - 2 is factor. So value of x is 2.
Substituting value of x we get,
p(x) = x3 - 3x + 5a
p(2) = 2*3 - 3(2) + 5a
0+ 8-6 + 5a
-2 = 5a
a= -0.4
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Answer:
<h2>absolute maximum = 16</h2><h2>absolute minimum = 1</h2>
Step-by-step explanation:
To get the absolute maximum and minimum values of the function f(x) = 16 + 2x − x² n the given interval [0,5], we need to get the values of f(x) at the end points. The end points are 0 and 5.
at x = 0;
f(0) = 16 + 2(0) − 0²
f(0) = 16
at the other end point i.e at x = 5;
f(5) = 16 + 2(5) − 5²
f(5) = 16 + 10-25
f(5)= 26-25
f(5) = 1
The absolute minimum value is 1 and occurs at x = 5
The absolute maximum value is 16 and occurs at x = 0
Answer: (6,0)
Step-by-step explanation: To find the x-intercept, we plug a 0 in for y.
So we have 2x - 3(0) = 12.
Simplifying from here, we have 2x = 12.
Now divide both sides by 2 and we get <em>x = 6</em>.
So our x-intercept is 6.
This means that our line crosses the x-axis 6
units to the right of the origin or at the point (6,0).
