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harina [27]
3 years ago
12

The first two numbers in a sequence h are h(1) = 2 and h(2) = 6.

Mathematics
1 answer:
Ghella [55]3 years ago
3 0

Answer:

Step-by-step explanation:

Given the first two numbers of a sequence as 2, 6...

If it is an arithmetic difference, the common difference will be d = 6-2 = 4

Formula for calculating nth term of an ARITHMETIC sequence Tn = a+(n-1)d

a is the first term = 2

d is the common difference = 4

n is the number if terms

Substituting the given values in the formula.

Nth term Tn = 2+(n-1)4

Tn = 2+4n-4

Tn = 4n-4+2

Tn = 4n-2

2) If the sequence us a geometric sequence

Nth term of the sequence Tn = ar^(n-1)

r is the common ratio

r is gotten by the ratio of the terms I.e

r = T2/T1

r = 6/2

r = 3

Since a = 2

Tn = 2(3)^(n-1)

Hence the nth term of the geometric sequence is Tn = 2(3)^(n-1)

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