Answer: a. BaO
Explanation:
For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.
Here element barium is having an oxidation state of +2 called as 
cation and 
is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral 
Answer:
yes
Explanation:
because chemical wheathering could wheather it away into a ditch
pH=6.98
Explanation:
This is a very interesting question because it tests your understanding of what it means to have a dynamic equilibrium going on in solution.
As you know, pure water undergoes self-ionization to form hydronium ions, H3O+, and hydroxide anions, OH−.
2H2O(l]⇌H3O+(aq]+OH−(aq]→ very important!
At room temperature, the value of water's ionization constant, KW, is equal to 10−14. This means that you have
KW=[H3O+]⋅[OH−]=10−14
Since the concentrations of hydronium and hydroxide ions are equal for pure water, you will have
[H3O+]=√10−14=10−7M
The pH of pure water will thus be
pH=−log([H3O+])
pH=−log(10−7)=7
Now, let's assume that you're working with a 1.0-L solution of pure water and you add some 10
Answer:
Explanation:
a) Volume of the gas nRT / P
= 1,04 X 8.3 X 298 / 11 X 10⁵ m³
= 233.85 x 10⁻⁵ m³
= 233 x 10⁻² L
2.33 L
P₁V₁ / T₁ =P₂V₂/T₂
(11 X 2.33) / 298 = (1 X 24.2) / T
T = 281.37 K
= 8.37 degree
b ) w = p x change in volume
= 10⁵ x ( 24.2 - 2.33 ) x 10⁻³ J
= 21.87 X 10² J
2187 J
q = n x Cp x (25 - 8.37 )
= 1.04 x 35.66x 16.63 J
= 616.65 J
ΔU = Q - W
= 616.65 - 2187 J
= - 1570.35 J
=
=
