A piece of lead with a mass of 14.9 grams at a temperature of 92.5 degrees Celsius is dropped into an insulated container of wat
er. The mass of the water is 165 g and its temperature before adding the lead is 20.00 degrees Celsius. After adding the lead to the water, the water temperature rises to 20.20 degrees Celsius. What is the specific heat of the lead?
2 answers:
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The equilibrium constant for the reaction is 0.00662
Explanation:
The balanced chemical equation is :
2NO2(g)⇌2NO(g)+O2(g
At t=t 1-2x ⇔ 2x + x moles
The ideal gas law equation will be used here
PV=nRT
here n= =
= density
P = density is 0.525g/L, temperature= 608.15 K, P = 0.750 atm
putting the values in reaction
0.75 =
M = 34.61
to calculate the Kc
Kc=
x M NO2 +
M NO+
M O2
Putting the values as molecular weight of NO2, NO,O2
34.61=
x= 0.33
Kc=
putting the values in the above equation
Kc = 0.00662