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3 years ago

5

A substance has a high melting point and conducts electricity in the liquid phase The is substance is

1 answer:

posledela3 years ago

3 0

Answer:

oxygen

Explanation:

?

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If an atom has 12 protons 12 neutrons, and 12 electrons, what is the charge of the atom?

Evgesh-ka [11]

I think the charge is +2
Hope this helps

6 0

3 years ago

The Andes Mountains are found along the western coast of South America. Which kind of plate boundary is responsible for this mou

lozanna [386]

The Nazca plate is converging with the South American plate.

Explanation:

The Andes Mountains are formed as a result of the convergent of the Nazca plate and the South American plate.

This mountain range typifies the geology and geography of the South American continent.

Along this convergent margin, one plate subducts beneath the other.
The oceanic plate due to its density goes into the mantle.
The causes the continent riding to obduct and be forced.
With rising magmatic bodies beneath, the continent further pushes up to form the Andes ranges.

Learn more:

Lithosphere brainly.com/question/9582362

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3 0

3 years ago

Calculate E ° for the half‑reaction, AgCl ( s ) + e − − ⇀ ↽ − Ag ( s ) + Cl − ( aq ) given that the solubility product constant

antoniya [11.8K]

Answer: The value of $E^{o}$ for the half-cell reaction is 0.222 V.

Explanation:

Equation for solubility equilibrium is as follows.

$AgCl(s) \rightleftharpoons Ag^{+}(aq) + Cl^{-}(aq)$

Its solubility product will be as follows.

$K_{sp} = [Ag^{+}][Cl^{-}]$

Cell reaction for this equation is as follows.

$Ag(s)| AgCl(s)|Cl^{-}(0.1 M)|| Ag^{+}(1.0 M)| Ag(s)$

Reduction half-reaction: $Ag^{+} + 1e^{-} \rightarrow Ag(s)$ , $E^{o}_{Ag^{+}/Ag} = 0.799 V$

Oxidation half-reaction: $Ag(s) + Cl^{-}(aq) \rightarrow AgCl(s) + 1e^{-}$ , $E^{o}_{AgCl/Ag}$ = ?

Cell reaction: $Ag^{+}(aq) + Cl^{-}(aq) \rightarrow AgCl(s)$

So, for this cell reaction the number of moles of electrons transferred are n = 1.

Solubility product, $K_{sp} = [Ag^{+}][Cl^{-}]$

= $1.77 \times 10^{-10}$

Therefore, according to the Nernst equation

$E_{cell} = E^{o}_{cell} - \frac{0.0592 V}{n} log \frac{[AgCl]}{[Ag^{+}][Cl^{-}]}$

At equilibrium, $E_{cell}$ = 0.00 V

Putting the given values into the above formula as follows.

$E_{cell} = E^{o}_{cell} - \frac{0.0592 V}{n} log \frac{[AgCl]}{[Ag^{+}][Cl^{-}]}$

$0.00 = E^{o}_{cell} - \frac{0.0592 V}{1} log \frac{1}{[Ag^{+}][Cl^{-}]}$

$E^{o}_{cell} = \frac{0.0592}{1} log \frac{1}{K_{sp}}$

= $0.0591 V \times log \frac{1}{1.77 \times 10^{-10}}$

= 0.577 V

Hence, we will calculate the standard cell potential as follows.

$E^{o}_{cell} = E^{o}_{cathode} - E^{o}_{anode}$

$0.577 V = E^{o}_{Ag^{+}/Ag} - E^{o}_{AgCl/Ag}$

$0.577 V = 0.799 V - E^{o}_{AgCl/Ag}$

$E^{o}_{AgCl/Ag}$ = 0.222 V

Thus, we can conclude that value of $E^{o}$ for the half-cell reaction is 0.222 V.

3 0

3 years ago

Which is a compound that contains carbon?

Anastaziya [24]

carbon dioxide, that is what I found

7 0

3 years ago

Pls help, WILL MARK BRAINLIEST FOR THE CORRECT ANSWER!!!!

Nitella [24]

Answer:

The answer is D. Substances Y and Z would react to replace substance W, and the position of equilibrium would shift to the left.

Explanation:

PLZ BRAINLIEST'!!!

6 0

3 years ago

Read 2 more answers