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marin [14]
3 years ago
10

PLZ ANSWER ASAP!

Mathematics
1 answer:
Lana71 [14]3 years ago
3 0
Well x^2+10x-3 is a quadratic so we are looking for its lowest point (minimum). If you graph it the answer is (-5, -28) so A. You can do it algebraicallly (x+5)=0. X=-5 and look at -28 for y. Either way you get A as the local minimum/ lowest point of graph.
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PLEASE HELP ASAP!!!<br> solve for the given variable and show your work. 3a-12b=30. solve for b.
olganol [36]

Answer:

b=(-10-a)/4

First factor out the common number:3

Then divide both sides by 3

Then simplify 30/3 to 10

Then subtract a to get your answer

5 0
3 years ago
Kai had 15 yards of kite string. He
n200080 [17]

Answer:

he cut 5 strings to pull it out

3 0
2 years ago
Please help me answer this worksheet (Geometry Worksheet 3.3)
AysviL [449]

As per the reference document attached thereby along with the question statement, if (∠SOX = 160°), [∠1 = (x + 14)], and [∠2 = (3x – 10)], then the measure of ∠2 in degrees will be 113°

As per the reference document attached thereby along with the question statement, (∠SOX = 160°), and it's constituent angles

[∠1 = ∠SOW = (x + 14)], and [∠2 = ∠WOX = (3x – 10)],

And we are required to determine the measure of ∠2.

Since, [(∠SOW + ∠WOX) = ∠SOX],

Therefore, [{(x + 14) + (3x – 10)} = 160°]

Or, [{(x + 3x) + (14 - 10)} = 160°]

Or, [(4x - 4) = 160°]

Or, [4x = (160 + 4)°]

Or, (4x = 164°)

Or, [x = (164/4)°]

Or, (x = 41°)

Or, [(3x – 10) = {(3 * 41) - 10}°]

Or, [∠2 = (123 - 10)°]

Or, (∠2 = 113°)

That is, if (∠SOX = 160°), and it's constituent angles (∠1) and (∠2) measure as [∠1 = ∠SOW = (x + 14)], and [∠2 = ∠WOX = (3x – 10)], then the measure of ∠2 in degrees will be 113°

To learn more about Measures in Degrees, click on the link below.

brainly.com/question/12362603

#SPJ1

4 0
1 year ago
-3/4 x (-10/9)<br><br> A. 27/40<br> B. 5/6<br> C. -27/40<br> D. -5/6
Alexeev081 [22]

Answer: B

Step-by-step explanation:

1. Multiplying two negatives equals a positive.

2. Reduce the numbers with the GCF, 3.

3. Reduce the numbers with the greatest common factor, 2.

4. Multiply the fractions which would give you: 5/6

3 0
2 years ago
Read 2 more answers
2. in a class of 50 students, the number of females is 2 more than 5 times the number of males. How many males and females are t
Ber [7]

Answer:

There are 8 males in the class and 42 females.

Step-by-step explanation:

This question can be solved using a system of equations.

I am going to say that:

x is the number of females.

y is the number of males.

Class of 50 students

This means that x + y = 50

The number of females is 2 more than 5 times the number of males.

This means that x = 5y + 2

So, finding y, the number of males:

x + y = 50

5y + 2 + y = 50

6y = 48

y = \frac{48}{6}

y = 8

Females:

x = 5y + 2 = 5*8 + 2 = 42

There are 8 males in the class and 42 females.

7 0
2 years ago
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