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marin [14]
3 years ago
10

PLZ ANSWER ASAP!

Mathematics
1 answer:
Lana71 [14]3 years ago
3 0
Well x^2+10x-3 is a quadratic so we are looking for its lowest point (minimum). If you graph it the answer is (-5, -28) so A. You can do it algebraicallly (x+5)=0. X=-5 and look at -28 for y. Either way you get A as the local minimum/ lowest point of graph.
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If you have 5\6 of a cup of flour, how many twelfths do you have
egoroff_w [7]

Answer:

10/12

Step-by-step explanation:

Multiply 5/6x2/2

6 0
3 years ago
What is the conjecture sentence for the pattern 1, ,4, 9 ,16?
nexus9112 [7]

Answer:

Square numbers

Step-by-step explanation:

if 1 is squared, you get 1.

if 2 is squared, you get 4.

if 3 is squared, you get 9.

if 4 is squared, you get 16.

And thus square numbers.

8 0
3 years ago
(100) points!!!! Help please
inysia [295]

Answer:

\displaystyle a_8=142,11\ mg

Step-by-step explanation:

Geometric sequence

Each term in a geometric sequence can be computed as the previous term by a constant number called the common ratio. The formula to get the term n is

\displaystyle a_n=a_1r^{n-1}

where a_1 is the first term of the sequence

The problem describes Georgie took 275 mg of the medicine for her cold in the first hour and that in each subsequent hour, the amount of medicine in her body is 91% (0.91) of the amount from the previous hour. It can be written as

amount in hour n = amount in hour n-1 * 0.91

a)

This information provides the necessary data to write the general term as

\displaystyle a_n=275\ .\ 0.91^{n-1}

b)

In the 8th hour (n=8), the remaining medicine present is Georgie's body is

\displaystyle a_n=275\ .\ 0.91^{8-1}

\displaystyle a_n=275\ .\ 0.91^{7}

\boxed{\displaystyle a_8=142,11\ mg}

6 0
3 years ago
What is 12+[(14-6)/4]
saveliy_v [14]

Answer:

14

Step-by-step explanation:

THE ANSWER TO THE PROBLEM IS 14

3 0
3 years ago
Find 7% of 3.1 trillion
wariber [46]

Answer:217,000,000,000 (or just plain 217000000000)


Step-by-step explanation:7% is 0.07.

0.07 * 3.1 trillion


5 0
3 years ago
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