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Fiesta28 [93]
3 years ago
5

Help help i need help anyone ?

Mathematics
1 answer:
REY [17]3 years ago
3 0
-9-6i/-3-2i
Factor -3 out of expression
-3(3+2i)/-3-2i
Then extract the negative sign out of the expression
-3(3+2i)/-(3+2i)
Reduce the fraction with -(3+2i)
-3/-1
-3*-1=3
Hope this helps
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Which statement about this figure is true?
LenKa [72]

Answer:

It has reflectional symmetry with four lines of symmetry. It has no rotational symmetry It has point symmetry. It has rotational symmetry with an angle of rotation of 90°.

6 0
3 years ago
Find the exact length of the curve. x=et+e−t, y=5−2t, 0≤t≤2 For a curve given by parametric equations x=f(t) and y=g(t), arc len
Rama09 [41]

The length of a curve <em>C</em> parameterized by a vector function <em>r</em><em>(t)</em> = <em>x(t)</em> i + <em>y(t)</em> j over an interval <em>a</em> ≤ <em>t</em> ≤ <em>b</em> is

\displaystyle\int_C\mathrm ds = \int_a^b \sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2} \,\mathrm dt

In this case, we have

<em>x(t)</em> = exp(<em>t</em> ) + exp(-<em>t</em> )   ==>   d<em>x</em>/d<em>t</em> = exp(<em>t</em> ) - exp(-<em>t</em> )

<em>y(t)</em> = 5 - 2<em>t</em>   ==>   d<em>y</em>/d<em>t</em> = -2

and [<em>a</em>, <em>b</em>] = [0, 2]. The length of the curve is then

\displaystyle\int_0^2 \sqrt{\left(e^t-e^{-t}\right)^2+(-2)^2} \,\mathrm dt = \int_0^2 \sqrt{e^{2t}-2+e^{-2t}+4}\,\mathrm dt

=\displaystyle\int_0^2 \sqrt{e^{2t}+2+e^{-2t}} \,\mathrm dt

=\displaystyle\int_0^2\sqrt{\left(e^t+e^{-t}\right)^2} \,\mathrm dt

=\displaystyle\int_0^2\left(e^t+e^{-t}\right)\,\mathrm dt

=\left(e^t-e^{-t}\right)\bigg|_0^2 = \left(e^2-e^{-2}\right)-\left(e^0-e^{-0}\right) = \boxed{e^2-\frac1{e^2}}

5 0
2 years ago
a seed company has a test plot in which it is testing the germination of a hybrid seed, They plant 50 rows of 40 seeds per row.
ziro4ka [17]

Answer:

Mean =\sum x P(x) = 36.86

Standard deviation =\sum x^2P(X)=1360.9

Step-by-step explanation:

x          P(x) x \times P(x)       x^2 \times  P(x)

33         0.02     0.66          21.78

34          0.06     2.04         69.36

35           0.1      3.5        122.5

36           0.2      7.2         259.2

37           0.24     8.88        328.56

38           0.26     9.88        375.44

39            0.1     3.9         152.1

40            0.02     0.8         32

             1        36.86      1360.9

We are supposed to find mean and standard deviation

Mean =\sum x P(x) = 36.86

Standard deviation =\sum x^2P(X)=1360.9

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Answer:

A

Step-by-step explanation:

the answer is A because I got it right on my test

7 0
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