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olganol [36]
2 years ago
14

What is the next term in this pattern 10, 8.9, 7.8, 6.7

Mathematics
1 answer:
Sladkaya [172]2 years ago
5 0

Answer:

5.6

Step-by-step explanation:

You just have to keeps subtracting 1.1

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What is the explicit rule for the sequence? −3, 0,3,6,9,... Enter your answer in the box.
PtichkaEL [24]

Answer:

  • aₙ = 3n - 6

Step-by-step explanation:

<u>Given sequence:</u>

  • −3, 0,3,6,9,...

<u>This is AP with:</u>

  • The first tern a₁ = - 3
  • Common difference d = 3

<u>The rule for the nth term of the sequence is:</u>

  • aₙ = a₁ + (n - 1)d

<u>Substitute values:</u>

  • aₙ = -3 + (n - 1)(3) =
  •       -3 + 3n - 3 =
  •        3n - 6

3 0
3 years ago
Identify as a direct variation, inverse variation or neither. The number of tons of coal burned by an old coal burning locomotiv
pochemuha
Answer: it is a direct variation.

Justification:

In a direct variation the variables are related by a proportionality constant in this way:

y = k x

Tthan means that the value of y is always the product of a constant times the value of x.

The situation discribed for the coal may be written as:
number of tons of coal burned: c

number of hours: h

⇒ c = k × h

Which is that you can calcualte the number of tons of coal burned at any time, once you know the proportionality constant k.




5 0
3 years ago
Need help please tell me the answers for each one
neonofarm [45]
The answer to the question

7 0
3 years ago
PLSS I NEED HELPPP .
Sidana [21]

Answer:

yes

Step-by-step explanation:

...........................

5 0
2 years ago
The mean of a list of test scores is 80. Adding an additional test score of 92 caused the mean to rise to 82. After this additio
miv72 [106K]

Answer:

6

Step-by-step explanation:

The mean of a list of test scores is 80

Adding an additional test score of 92 caused the mean to rise to 82

To find:

After this additional, how many total test are in the list ?

Solution:

Let the total number of test at first = n

And sum of total score = S

As we know, mean = \frac{sum \ of \ total \ observation}{number\  of \ total\  observation}

                    80= \frac{S}{n} \\

Multiplying both sides by n

80n=S

Now, as adding an additional test score of 92 caused the mean to rise to 82,

S+92=82\times(n+1)\\80n +92 = 82n+82           \  (given \ S =80n)

80n-82n =82-92\\-2n=-10

By dividing both sides by minus ( - )

2n =10

By dividing both sides by 2

n =5

Thus, total number of test at first = n = 5

And, after this additional score added, total number of tests are n+1=6

4 0
2 years ago
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