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3 years ago

HURRY TIMEDD!!!!!

Mathematics

1 answer:

Anestetic [448]3 years ago

7 0

Answer:

Second option is the correct choice.

Step-by-step explanation:

"The discriminant is −4, so the equation has no real solutions."

$x^2-4x+5=0\\\\a=1,\:b=-4,\:c=5:\\\\b^2-4ac=\left(-4\right)^2-4\cdot \:1\cdot \:5=-4$

Best Regards!

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Convert 12 and a half of 30

tamaranim1 [39]

Answer:

375

Step-by-step explanation:

12½[30] → 25⁄2[30]

Multiply 25 by 30 [750] then divide by 2 to get 375.

I am joyous to assist you anytime.

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3 years ago

Please Help! Malik agreed to practice basketball drills with a new player, Tyler, during practice. Malik's best friend, Samuel,

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Malik can remain honest with his partner Samuel and respect his opinion.

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2 years ago

Please help ASAP!! it’s for geometry

ikadub [295]

The answer is D.

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3 years ago

What is a cubic polynomial function with zeros 3,3 and -3? show your work.

Brums [2.3K]

Answer:

Cubic polynomial function with zeros 3,3 and -3 is $\mathbf{x^3-3x^2-9x+27=0}$

Step-by-step explanation:

We need to find a cubic polynomial function with zeros 3,3 and -3.

If zeros of polynomial are: 3,3,and -3

we can write:

x=3, x=3, x=-3

We can write:

x-3=0, x-3=0, x+3=0

Now, we can write them as:

(x-3)(x-3)(x+3)=0

Multiplying the terms, we can find the polynomial:

$(x-3)(x-3)(x+3)=0\\(x(x-3)-3(x-3))(x+3)=0\\(x^2-3x-3x+9)(x+3)=0\\(x^2-6x+9)(x+3)=0\\x(x^2-6x+9)+3(x^2-6x+9)=0\\x^3-6x^2+9x+3x^2-18x+27=0\\x^3-6x^2+3x^2+9x-18x+27=0\\x^3-3x^2-9x+27=0$

So, cubic polynomial function with zeros 3,3 and -3 is $\mathbf{x^3-3x^2-9x+27=0}$

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3 years ago

Solve for x. x/3≤—6 1.x≤—2 2.x≤—18 3.x≥—2 4.x≥—18

RSB [31]

Answer:

$x \leqslant - 18$

Step-by-step explanation:

Multiply both sides by 3

$x \leqslant - 18$

6 0

3 years ago