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3 years ago

I want to know how to expand x(4 - 3.4y)

Mathematics

2 answers:

Fittoniya [83]3 years ago

8 0

Answer:

X(4-3.4y)

= 4x - 3.4xy

Step-by-step explanation:

Alex73 [517]3 years ago

6 0

X(4-3.4y)
= 4x - 3.4xy

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Solve for M -3+m/ 9 = 10

sweet-ann [11.9K]

Step-by-step explanation:

-3+m/9=10

m/9=10+3

m/9=13

m=13×9

m=117

Note:if you need to ask any question please let me know.

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2 years ago

Which Graph correctly solves the equation below? -1/2x^2 +2 = 2x^2 -8

lubasha [3.4K]

Answer:

see attachment

Step-by-step explanation:

The given equation is

$- \frac{1}{2} {x}^{2} + 2 = 2 {x}^{2} - 8$

The graph of the left hand side of this equation is

$y = - \frac{1}{2}{x}^{2} + 2$

This quadratic graph has its vertex at (0,2) and turns upside down.

The right hand side of the equation is

$y = 2 {x}^{2} - 8$

This quadratic graph opens upwards and has its vertex at (0,-8).

The two graphs intersects at two points , which are (-2,0) and (2,0).

6 0

3 years ago

What is the median of 4, 6, 9, 11, 8, 13, 12

Talja [164]

Write the numbers in order first,
4, 6, 8, 9, 11, 12, 13
Middle number in sequence is the median, in this case median is 9.

5 0

3 years ago

Read 2 more answers

If cos() = − 2 3 and is in Quadrant III, find tan() cot() + csc(). Incorrect: Your answer is incorrect.

nydimaria [60]

Answer:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

Step-by-step explanation:

Given

$\cos(\theta) = -\frac{2}{3}$

$\theta \to$ Quadrant III

Required

Determine $\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

We have:

$\cos(\theta) = -\frac{2}{3}$

We know that:

$\sin^2(\theta) + \cos^2(\theta) = 1$

This gives:

$\sin^2(\theta) + (-\frac{2}{3})^2 = 1$

$\sin^2(\theta) + (\frac{4}{9}) = 1$

Collect like terms

$\sin^2(\theta) = 1 - \frac{4}{9}$

Take LCM and solve

$\sin^2(\theta) = \frac{9 -4}{9}$

$\sin^2(\theta) = \frac{5}{9}$

Take the square roots of both sides

$\sin(\theta) = \±\frac{\sqrt 5}{3}$

Sin is negative in quadrant III. So:

$\sin(\theta) = -\frac{\sqrt 5}{3}$

Calculate $\csc(\theta)$

$\csc(\theta) = \frac{1}{\sin(\theta)}$

We have: $\sin(\theta) = -\frac{\sqrt 5}{3}$

So:

$\csc(\theta) = \frac{1}{-\frac{\sqrt 5}{3}}$

$\csc(\theta) = \frac{-3}{\sqrt 5}$

Rationalize

$\csc(\theta) = \frac{-3}{\sqrt 5}*\frac{\sqrt 5}{\sqrt 5}$

$\csc(\theta) = \frac{-3\sqrt 5}{5}$

So, we have:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \tan(\theta) \cdot \frac{1}{\tan(\theta)} + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 + \csc(\theta)$

Substitute: $\csc(\theta) = \frac{-3\sqrt 5}{5}$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 -\frac{3\sqrt 5}{5}$

Take LCM

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

6 0

3 years ago

357 miles in 6.3 hours

FromTheMoon [43]

Speed: 357 miles : 6.3 hours = 357 : 63/10 = 357 * 10/63 = 3570/63 = 56 42/63 mph

7 0

2 years ago