Answer:
-2/5 would be 2 down and 5 right
The system of equations has the solution:
x = 111/42
y = 27/14
z = -15/6
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How to solve the system of linear equations?</h3>
We start with 3 linear equations:
2x+y-z=8
x+4y+z=7
-3x+2y-3z=21
To solve this, first we need to isolate one of the variables. I will isolate x on the second one:
x = 7 - 4y - z
Now we can replace that in the other two:
2*( 7 - 4y - z) + y - z = 8
-3*(7 - 4y - z) + 2y - 3z = 21
Now we need to isolate other variable, let's isolate y on the above one:
14 - 8y - 2z + y - z = 8
-7y - 3z = 8 - 14 = -6
z = (-6 + 7y)/-3 = 2 - (7/3)*y
Now we replace this on the last equation:
-21 + 12y -3z + 2y - 3z = 21
14y - 6z = 42
14y - 6*(2 - (7/3)*y) = 42
14y - 12 + 14y = 42
28y = 42 + 12 = 54
y = 54/28 = 27/14
Now that we know the value of y, we can find the value of z:
z = 2 - (7/3)*y = 2 - (7/3)*27/14 = 2 - 27/6 = -15/6
And the value of x:
x = 7 - 4y - z = 7 - 4*(27/14) + 15/6 = 7 - 48/7 + 15/6 = 111/42
So the solution is:
x = 111/42
y = 27/14
z = -15/6
If you want to learn more about systems of equations:
brainly.com/question/13729904
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Multiply each number by 3
1x3=3
3x3=9
9x3=27
27x3=81
I would say 90 but I could be wrong because if the tents edge is 30 feet and she walks at the edge twice it would be 60 but when she go back wouldn’t that be the same distance so 90.
Correct me if I’m wrong