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3 years ago

Theoretical probability is based on the assumption that all outcomes in the sample space occur

2 answers:

6 0

It is <u>true </u>that t<span>heoretical probability is based on the assumption that all outcomes in the sample space occur randomly.
Probability refers to the fact the chances of these outcomes to occur, which means that there is no pattern. </span>

morpeh [17]3 years ago

4 0

The answer is A. The statement is true. It is called probability because the samples are taken randomly.

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many credit card companies charge a compound interest of 1.8% per month on a credit card balance. Miriam owes 750 on a credit ca

nadya68 [22]

Answer:

Most credit card companies also apply a late payment penalty if you owe a balance and do not make a payment. Ignoring that fee, Miriam's balance will increase as:

B(n) = 750(1.018)^n

where B(n) is Miriam's balance after n months. The progression will be:

$750.00

$763.50

$777.24

$791.23

$805.48

Step-by-step explanation:

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3 years ago

Read 2 more answers

What does the dotted line in the diagram imply about the number of triangles you can construct from the given information

nekit [7.7K]

Answer:

Step-by-step explanation:A triangle is aptly named: it is composed of three (tri) angles formed by three non-coincident, non-parallel lines. That the lines are non-coincident means they do not overlap, and that they are non-parallel means that each line intersects with every other line. Correspondingly, a triangle also has three sides.

3 0

3 years ago

The equation giving a family of ellipsoids is u = (x^2)/(a^2) + (y^2)/(b^2) + (z^2)/(c^2) . Find the unit vector normal to each

Fynjy0 [20]

Answer:

$\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

Step-by-step explanation:

Given equation of ellipsoids,

$u\ =\ \dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2}$

The vector normal to the given equation of ellipsoid will be given by

$\vec{n}\ =\textrm{gradient of u}$

$=\bigtriangledown u$

$=\ (\dfrac{\partial{}}{\partial{x}}\hat{i}+ \dfrac{\partial{}}{\partial{y}}\hat{j}+ \dfrac{\partial{}}{\partial{z}}\hat{k})(\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2})$

$=\ \dfrac{\partial{(\dfrac{x^2}{a^2})}}{\partial{x}}\hat{i}+\dfrac{\partial{(\dfrac{y^2}{b^2})}}{\partial{y}}\hat{j}+\dfrac{\partial{(\dfrac{z^2}{c^2})}}{\partial{z}}\hat{k}$

$=\ \dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}$

Hence, the unit normal vector can be given by,

$\hat{n}\ =\ \dfrac{\vec{n}}{\left|\vec{n}\right|}$

$=\ \dfrac{\dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}}{\sqrt{(\dfrac{2x}{a^2})^2+(\dfrac{2y}{b^2})^2+(\dfrac{2z}{c^2})^2}}$

$=\ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

Hence, the unit vector normal to each point of the given ellipsoid surface is

$\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

3 0

3 years ago

Please help me with my algebra homework thank you

kumpel [21]

Answer:

a.) 5x

b.) 6xy

c.) 6xy

Step-by-step explanation:

5 * x = 5x

6 * x * y = 6xy

2 * x * 3 * y = 6xy