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Hoochie [10]
2 years ago
14

What is 17x greater than -17?

Mathematics
1 answer:
lesya [120]2 years ago
5 0

Answer:

Step-by-step explanation:

Any number that times 17 is bigger than -17

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You are dealt one card from a 52 - card deck. what is the probability that you are NOT dealt a diamond ?
astra-53 [7]
Since there are 13 diamonds, there are 39 non diamonds (52-13)
To write a probability, you put the part over the whole
So you get 39/52 which is simplified to 3/4 so C

Hope this helps
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What is 75% as a fraction in simplest form
ludmilkaskok [199]
75% = 75/100÷ 5= 15/20 ÷5= ¾. does this help? hope it does
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7 0
2 years ago
Tara had $350 in her bank account she received three birthday checks for $35 each and but bought two new video games for $41 eac
goldfiish [28.3K]

We conclude that the final amount that she has in her bank account is $375.

<h3>How much has Tara in her bank account now?</h3>

Here we need to perform some additions and subtractions. We know that Tara starts with $350 in her account.

Then she received 3 checks for $35 each, so at this point she has:

$350 + 3*$35 = $455

Now she buys 2 video games for $41 each, so we need to subtract two times $41, we will get:

$455 - 2*$41 = $375

We conclude that the final amount that she has in her bank account is $375.

If you want to learn more about additions and subtractions:

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6 0
1 year ago
Hey Bestie! 50 pts Pls help! Real answers only pls &lt;3
frosja888 [35]

Answer:

1. \: 3i

2. option D

3. option C

4. option D

5. option C

6. option B

7. option C

8. option D

9. option C

10. option C

Step-by-step explanation:

<h2>1. \:  \sqrt{ - 9}</h2>

\sqrt{ - 1(9)}

\sqrt{ - 1}  \times  \sqrt{  9}

i \times  \sqrt{9}

i \times  \sqrt{ {3}^{2} }

i \times 3

3i

<h2>2. \:  \sqrt{ - 8}</h2>

\sqrt{ - 1(8)}

\sqrt{ - 1}  \times  \sqrt{8}

i \times  \sqrt{8}

i \times  \sqrt{ {2}^{2} \times 2 }

2i \sqrt{2}

<h2>3. \:  \sqrt{ - 80}</h2>

\sqrt{ - 1}  \times  \sqrt{80}

i \times  \sqrt{80}

4i \:  \sqrt{5}

<h2>4. \:  \sqrt{ - 75}</h2>

\sqrt{ - 1}  \times   \sqrt{75}

i \times  \sqrt{75}

i \times  \sqrt{ {5}^{2} \times 3 }

5i \sqrt{3}

<h2>5. \:  \sqrt{ - 72}</h2>

\sqrt{ - 1}  \times  \sqrt{72}

i \times  \sqrt{72}

i \times ( {6}^{2}  \times 2)

6i \sqrt{2}

<h2>6.  \sqrt{ - 20}</h2>

\sqrt{ - 1}  \times  \sqrt{20}

i \times  \sqrt{20}

i \times  \sqrt{ {2}^{2}  \times 5}

2i \sqrt{5}

<h2>7. \:  \sqrt{ - 27}</h2>

\sqrt{ - 1}  \times  \sqrt{27}

i \times  \sqrt{27}

i \times  \sqrt{ {3}^{2}  \times 3}

3i \sqrt{3}

<h2>8. \:  \sqrt{ - 12}</h2>

\sqrt{ - 1 \times 12}

i \times  \sqrt{12}

i \times  \sqrt{4(3)}

2i \sqrt{3}

<h2>9. \:  \sqrt{ - 125}</h2>

\sqrt{ - 1}  \times  \sqrt{125}

i \times  \sqrt{ {5}^{2} \times 5 }

5i \sqrt{5}

<h2>10. \:  \sqrt{ - 180}</h2>

\sqrt{ - 1}  \times  \sqrt{180}

i \times  \sqrt{ {6}^{2} \times 5 }

6i \sqrt{5}

<h3>Hope it is helpful...</h3>
5 0
2 years ago
When rolling a number cube (dice), find: P(a number less than 3)
I am Lyosha [343]
A number less than three would be 1 or 2.
6 0
1 year ago
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