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4 years ago

Factor the polynomial.

2 answers:

8 0

It is answer choice A because you have to take the the GCF of each number which is 2x. Then if you were to divide the numbers by 2x you would put those numbers in the brackets.
$2x( x^{2} +2x+4)$ because $2x^3/2 x = x^{2}$ and $4 x^{2} /2x = 2x$ and $8x/2x = 4$

zzz [600]4 years ago

3 0

Factor out 2x to get 2x(x^2+2x+4). This cannot be factored further, so A is the answer.

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What is the initial value, and what does it represent?

inn [45]

Answer:

A. The initial value is 100; it represents money left over from last year's fundraiser

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Factor the expression: 625t^5-1715t^2 Please show steps!

NeX [460]

Answer:

5 $t^{2}$ (5t-7)(25 $t^{2}$ +35t+49)

Step-by-step explanation:

5 0

3 years ago

Lexie began making posters for the school awards banquet. She can make 6 posters per minute. Zach joined her 10 minutes after sh

Snowcat [4.5K]

10 * 6 = 60 by the time Zach joins so 125-60 = 65
Now 6 (lexie) +7 (zach) = 13 (together) and 65/13 = 5.
6*5 = 30 and 7*5 = 35. 35+30 = 65
Your answer is 5.

7 0

4 years ago

| 9. The distance between Town A and Town B was 108 km. A car and a van left Town A at 12 00 for Town B. On reaching Town B, the

Westkost [7]

Answer:

a) Time until both vehicles meet is 1.5 hours after starting at noon. That makes it 1:30PM.

b) Average speed of car is 84 km/h

Step-by-step explanation:

A -----------------------z------------B

Left Speed(km/h) Time

Car: 12PM X

Van: 12PM 60

Car/Van

DistanceCar AB + z

DistanceVan Az

Ratio: (AB+z)/Az = 7/5

Time until both meet = T (in hours)

Distance Car: xT

Distance Van: 60T

====

xT = AB + z

60T = Az

---

(xT/60T)= (7/5)

x = 60(7/5)

x = 84 km/h

=====

Time for car to reach B is: time (hr) = 108 km/(84 km/h)

time = 1.286 hours

Distance for at 1.289 hours is: distance (km) = (60 km/h)*(1.286 h)

distance = 77.14 km

At 1.286 hours, the car reverses direction. The van is (108 km - 77.14 km) or 30.86 km away.

Add the distances travelled by both vehicles after the car reverses direction at 1.286 hours. The sum will be 30.86 km when they meet, at time of T.

Car Distance + Van Distance = 30.86 km

T(84 km/h) + t(60 km)

They meet when they are 0 km apart, which can be modeled with the following equation:

Van travel Distance - Car Travel Distance = 0 starting at 1.286 hr.

Let t be the time after 1.286 hours that both vehicles meet/collide.

t*(60 km/h) + t(84 km/h) = 30.86 km

t(60+84) = 30.86 km

t(144 km/h) = 30.86 km

t = 0.2143 hr

Total time until the car and van meet is 1.286 hr + 0.2143 hr for a total of 1.50 hours.

=================

a) Time until both vehicles meet is 1.5 hours after starting at noon. That makes it 1:30PM.

b) Average speed of car is 84 km/h

==============

CHECK

Is the ratio of the distance travelled by the car and the van until they meet in the ratio of 7/5?

Car distance is (1.5 hr)(84 km/h) = 126 km

Van distance is (1.5 hr)(60 km/h) = 90.0 km

Ratio is 126/90 or 1.4

Ratio of 7/5 is 1.4

YES

3 0

2 years ago

Select the expressions that are equivalent to 10 + 2x + 5y + 3x.

Ierofanga [76]

:D :D :D :D :D :D :D :D

3 0

3 years ago