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7nadin3 [17]
3 years ago
7

Lexie began making posters for the school awards banquet. She can make 6 posters per minute. Zach joined her 10 minutes after sh

e started. He can make 7 posters per minute. Lexie continued to make 6 posters per minute. Together, they made 125 posters. How many posters did zach make?
Mathematics
1 answer:
Snowcat [4.5K]3 years ago
7 0
10 * 6 = 60 by the time Zach joins so 125-60 = 65
Now 6 (lexie) +7 (zach)  = 13 (together) and 65/13 = 5. 
6*5 = 30 and 7*5 = 35. 35+30 = 65
Your answer is 5. 
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Answer:

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2x+8y+−8y=6+−8y

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Step 2: Divide both sides by 2

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7 0
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In 2000, the circulation of a local newspaper was 3,250. In 2001, its circulation was 3,640. In 2002, the circulation was 4,100.
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Percent increase from 2000 to 2001 is 12% and from 2001 to 2002 is 12.6%. Thus period of 2001 to 2002 has higher increase percentage.

<u>Solution:</u>

Given that,

Total circulation of local newspaper in 2000 = 3250

Total circulation of local newspaper in 2001 = 3640

Total circulation of local newspaper in 2002 = 4100

<em><u>Finding percent of increase in the newspaper’s circulation from 2000 to 2001:</u></em>

\text { Percent increase from } 2000 \text { to } 2001=\frac{\text { change in circulation from 2001 - 2000 }}{\text { circulation in } 2000} \times 100

\begin{array}{l}{=\frac{3640-3250}{3250} \times 100} \\\\ {=\frac{390}{3250} \times 100=12 \%}\end{array}

<em><u>Finding percent of increase in the newspaper’s circulation from 2001 to 2002:</u></em>

\begin{array}{l}{\text { Percent increase from } 2001 \text { to } 2002=\frac{\text { change in circulation }}{\text {circulation in } 2001} \times 100} \\\\ {=\frac{4100-3640}{3640} \times 100} \\\\ {=\frac{460}{3640} \times 100=12.6 \%}\end{array}

As we can see 12% < 12.6%

So period of 2001 to 2002 has higher increase percentage.

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Answer:

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Step-by-step explanation:

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