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Rudiy27
3 years ago
15

Which is greater .83 or .083?

Mathematics
1 answer:
Serggg [28]3 years ago
8 0
.83 is greater .038 is in the thousands place and .83 is in the hundreds hope this Helped :D
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What set of reflections and rotations would carry rectangle ABCD onto Itself? (4 polnts)
shtirl [24]

Answer:

answer is b

Step-by-step explanation:

because photomath said so

7 0
3 years ago
If y varies directly as x, and y is 400 when x is randy is r when x is 4, what is the numeric constant of variation in this rela
juin [17]

The numeric constant of variation is 100

Step-by-step explanation:

Direct proportion means that increase in one variable cause increase in other variable

Here,

It is given that

y varies directly as x

y∝x

when the proportionality symbol is removed a proportionality constant is introduced

y = kx

Given that

y = 100 when x = 4

Putting the values

400 = k * 4\\k = \frac{400}{4}\\k = 100

The numeric constant of variation is 100

Keywords: Proportion variation

Learn more about direct proportion at:

  • brainly.com/question/1234767
  • brainly.com/question/1232765

#LearnwithBrainly

5 0
3 years ago
A gas station stores its gasoline in a tank under the ground. The tank is a cylinder lying horizontally on its side. (In other w
hoa [83]

Answer:

64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.

Step-by-step explanation:

Volume of cylinder = V

Radius of cylinder = r = 0.5 m

Height of the cylinder = 5 m

Volume of cylinder = \pi r^2h

V=3.14\times (0.5 m)^2\times 5 =3.925 m^3

Mass of gasoline = m

Density of gasoline = d = 673 kg/m^3

m=d\times V=673 kg/m^3\times 3.925 m^3=2,641.525 kg

Work done to pump the gasoline out of the tank W

Acceleration due to gravity = g .8 m/s^2

The center of gravity of fuel in fully filled tank will be centre so, the value of h = 2 m + 0.5 m = 2.5 m

W =m\times g\times h

W=2,641.525 kg\times 9.8 m/s^2\times 2.5 m=64,717.36 J

64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.

6 0
3 years ago
The hypotenuese of an isosceles right triangle is 16 inches. The midpoints of its sides are connected to form an inscribed trian
ser-zykov [4K]

Answer:

  256/3 = 85 1/3 square inches

Step-by-step explanation:

The dimensions of the first inscribed triangle are 1/2 those of the original, so its area is (1/2)² = 1/4 of the original. The area of the original is ...

  A = (1/2)bh = (1/2)(16/√2)(16/√2) = 64 . . . . square inches

The sum of an infinite series with first term 64 and common ratio 1/4 is ...

  S = a1/(1 -r) . . . . . . for first term a1 and common ratio r

  = 64/(1 -1/4) = 64(4/3) = 256/3 . . . . square inches

The sum of the areas of the triangles is 256/3 = 85 1/3 square inches.

3 0
3 years ago
Please help!! i will give brainliest!!
ZanzabumX [31]
If it is 5ft a minute then it must be 10ft every two minutes
3 0
2 years ago
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