Answer:
EB ≈ 1.563 in
Step-by-step explanation:
The diagonals of a rhombus divide the figure into four congruent right triangles. Angle DAB is bisected by EA, so angle EAB is 46°/2 = 23°. EB is the side opposite, so the relevant trig relation is ...
Sin = Opposite/Hypotenuse
sin(EAB) = EB/AB
EB = (4 in)sin(23°) . . . . . . multiply by the hypotenuse
EB ≈ 1.563 in
Answer:

Step-by-step explanation:
in this case we have a right angled triangle, whenever you see this triangle think of the TRIG RATIOS * sin, cos & tan* but if it was another triangle besides right angled triangle you use SINE RULE OR COSINE RULE
SOLUTION

Answer: 
Step-by-step explanation:
In order to solve this exercise it is important to remember the multiplication of signs. Notice that:

In this case you have the following expression given in the exercise:

Where the variable is "j".
When you multiply signs, you get:

Now you need to identify that like terms and then you need to add them (or combine them). So, applying this procedure you get that the simplified form of the expression is the shown below:

As you can observe, you get a 2nd degree binomial.
A parent function is normally not streched or anything or shhifted
y=kx or
y=x^a or
y=a^x are exapmles
y=x is y=1x
y=2x^3 is not it because the parent would be y=x^3
y=1/x is y=x^-1
y=2^x is y=2^x
answer is 2x^3 is not a parent function
Answer:
x = log 7
Step-by-step explanation:
10^x=7
Take the log base 10 on each side
log10 (10^x)=log10 (7)
We dont need to write the 10, it is implied
log(10^x)=log (7)
The exponent goes out front since log a^b = b log a
x log 10 = log 7
log 10 = 1 since the base is 10 log10(10) =1
x = log 7