First set up equation
x times y=xy
so
xy=-29
and
x+y=1
subtract x from both sides
y=1-x
subsitute 1-x for y in first equation
x(1-x)=-29
distribute
x-x^2=-29
add x^2 to both sides
x=-29+x^2
subtract x from both sides
0=x^2-x-29
so we can use the quadratic formula to solve for x if the equation=0 and it is in ax^2+bx+c form so
if
ax+bx+c=0 then x=

that means x=

or x=

so
x^2-x-29
a=1
b=-1
c=-29

=
![\frac{ +1-\sqrt{1^2-(-116)} }{2(1)}=\frac{ +1-\sqrt{1^2+116} }{2}=\frac{ +1-\sqrt{117} }{2}= \frac{1-10.816653826392}{2} = [tex] \frac{-9.816653826392}{2}= -4.908326913196](https://tex.z-dn.net/?f=%5Cfrac%7B%20%2B1-%5Csqrt%7B1%5E2-%28-116%29%7D%20%7D%7B2%281%29%7D%3D%5Cfrac%7B%20%2B1-%5Csqrt%7B1%5E2%2B116%7D%20%7D%7B2%7D%3D%5Cfrac%7B%20%2B1-%5Csqrt%7B117%7D%20%7D%7B2%7D%3D%20%5Cfrac%7B1-10.816653826392%7D%7B2%7D%20%3D%20%5Btex%5D%20%5Cfrac%7B-9.816653826392%7D%7B2%7D%3D%20-4.908326913196)
the second number is

the two numbers are
5.908326913196 and
-4.908326913196
D because there are two "wholes" and they are split up into 3 peices each. 2 divided by 1/3 will equal 6 because you split one "whole" into three parts and do teh same with the other.
Let us say the price of a table is
and a price of a chair
. Using this terminology we can say that the cost of 2 chairs and 5 tables is
. We have a second equation though,
from a table being 30 more than the price of a chair. Using this we can solve the system of equations. I think substitution is the quickest way to do this. Plug x from our second equation into the first equation.

This will simplify to the price of a chair is Rs 320. And add Rs 30 to that and we can find that the price of a table is Rs 350.
It is always good to check. So go ahead and check
to see that the first equation works (we know the second equation works just by eyeballing. And it looks like the cost is Rs 2300! Hooray!
Answer:

Step-by-step explanation:
see the attached figure to better understand the problem
we know that
In the right triangle ABC, the tangent of angle of 30 degrees is equal to divide the opposite side to the angle of 30 degrees (AC) by the adjacent side to the angle of 30 degrees (BC)

substitute the given values

Solve for b
