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Maurinko [17]
4 years ago
13

the mean cost of domestic airfares is RS 385 per ticket. Airfares were based on the total ticket value, which consisted of the p

rice charged by the airlines plus any additional taxes and fees. Assume domestic airfares are normally distributed with a standard deviation of RS 110. What is the probability that a domestic airfare is RS 550 or more?
Mathematics
1 answer:
Vladimir [108]4 years ago
7 0

Answer: 0.0668

Step-by-step explanation:

Given the following :

Mean (m) Cost = RS385

Standard deviation (s) = RS110

Assume a normal distribution, Probability that domestic airfare is RS550 or more?

P(x > 550)

Find the z - score

Z - score = (x - m) / s

Where x = 550

Z = (550 - 385) / 110

Z = 165 / 110 = 1.5

P(Z > 1.5) = 1 - P(Z ≤1.5)

Using the z table : 1.5 = 0.9332

Therefore,

1 - P(Z ≤1.5) = 1 - 0.9332 = 0.0668

P(x > 550) = 0.0668

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