Ask question

Ask question

All categories

3 years ago

7

Simplify -6+4{14+2[60-9(1+3)]}

1 answer:

ICE Princess25 [194]3 years ago

6 0

Answer:

242

Step-by-step explanation:

You might be interested in

Help plzzzzzz plz help this ? is realy hard Simplify the expression 7(a−3+4b).

velikii [3]

7(a−3+4b)

distribute

7a-7*3+7*4b

7a-21+28b

4 0

3 years ago

Read 2 more answers

What is the length of BC , rounded to the nearest tenth?

Arte-miy333 [17]

Step $1$

In the right triangle ADB

<u>Find the length of the segment AB</u>

Applying the Pythagorean Theorem

$AB^{2} =AD^{2}+BD^{2}$

we have

$AD=5\ units\\BD=12\ units$

substitute the values

$AB^{2}=5^{2}+12^{2}$

$AB^{2}=169$

$AB=13\ units$

Step $2$

In the right triangle ADB

<u>Find the cosine of the angle BAD</u>

we know that

$cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}$

Step $3$

In the right triangle ABC

<u>Find the length of the segment AC</u>

we know that

$cos(BAC)=cos (BAD)=\frac{5}{13}$

$cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{13}{AC}$

solve for AC

$AC=(13*13)/5=33.8\ units$

Step $4$

<u>Find the length of the segment DC</u>

we know that

$DC=AC-AD$

we have

$AC=33.8\ units$

$AD=5\ units$

substitute the values

$DC=33.8\ units-5\ units$

$DC=28.8\ units$

Step $5$

<u>Find the length of the segment BC</u>

In the right triangle BDC

Applying the Pythagorean Theorem

$BC^{2} =BD^{2}+DC^{2}$

we have

$BD=12\ units\\DC=28.8\ units$

substitute the values

$BC^{2}=12^{2}+28.8^{2}$

$BC^{2}=973.44$

$BC=31.2\ units$

therefore

<u>the answer is</u>

$BC=31.2\ units$

8 0

3 years ago

Read 2 more answers

A line had a slope of 2/3 and a y intercept at (0,14).What is the x intercept of the line?

pychu [463]

Answer:

y=2/3x+14

Step-by-step explanation:

The standard form of an equation in slope-intercept form is y=mx+b where m=slope and b=y-intercept.

Given a y-intercept of 14 and a slope of 2/3, we can plug into the variables and get the equation y=2/3x+14

The x-intercept would be when y=0, so plugging in y=0 to the equation gets us:

0=2/3x+14

-14=2/3x

21=x

So the x-intercept is 21

6 0

2 years ago

.Given: F(x) = 3x2+ 1, G(x) = 2x - 3, H(x) = x

inna [77]

For this case we have the following functions:

$F (x) = 3x ^ 2 +1\\G (x) = 2x-3\\H (x) = x$

We have to:

$G (x) * - 1$ is given by:

$(2x-3) * - 1 = -2x +3$

Thus, the correct option is the option is A.

On the other hand,

$F (x) +G (x) = 3x ^ 2 +1 +(2x - 3) = 3x ^ 2+ 1+ 2x-3 = 3x ^ 2 +2x-2$

Thus, the correct option is the option is A.

We also have:

$F (-2) = 3 (-2) ^ 2+ 1 = 3 (4)+ 1 = 12+ 1 = 13$

Thus, the correct option is the option is B.

Last we have:

$F (3)+G (4) -2H (5) = (3 (3) ^ 2+ 1)+ (2 (4) -3) -2 (5) = (3 (9)+ 1) - (8-3) 10 = 28+ 5-10 = 33$

Thus, the correct option is the option is C.

ANswer:

Option A, A, B, C

8 0

3 years ago

there is a 20% discount with a set of tires in normally sells for $368. How much will be tires cost after the discount?

ICE Princess25 [194]

Same as before, if we take 368 to be the 100%, how much is 20% off that?

$\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
368&100\\
d&20
\end{array}\implies \cfrac{368}{d}=\cfrac{100}{20}\implies \cfrac{368\cdot 20}{100}=d$

so, the discount is that much, thus, the discounted price is then 368 - d.

8 0

2 years ago