Answer:
(6,0)
Step-by-step explanation:
The coordinates of the points dividing the line segment in ratio m:n can be calculated as:

Here x1, y1 are the coordinates of first point S (-2, -6) and x2, y2 are the coordinates of second point T(18, 9).
In this case m will be 2 and n will be 3 as the ratio is 2:3
Using all these values we can find the coordinates of point Q

Thus, the coordinates of point Q which divides the line segment ST in ratio of 2:3 are (6,0)
Answer:
minimum value of function is
.
Step-by-step explanation:
Given function represents a parabola.
Now, here coefficient of
is positive , so the parabola will be facing upwards and thus the function will be having a minimum.
Now, as we know that minimum value of a parabolic function occurs at
x =
.
Where , b represents the coefficient of x and a represents the coefficient of
.
here, a = 2 , b = -6
Thus
=
=
So, at x =
minimum value will occur and which equals
y = 2×
-
+ 9 =
.
Thus , minimum value of function is
.
Answer:
a= 40-3b-c/5
a=-10+3b-2c
a=50+2b-3c/14
Step-by-step explanation:
5a+3b+c-(3b+c)=40-(3b+c)
5a=40-3b-c
5a/5=40/5-3b/5-c/5
a= 40-3b-c/5
a-3b+2c-(3b+2c)=-10-(-3b+2c)
a=-10+3b-2c
14a-2b+3c-(-2b+3c)=50-(-2b+3c)
14a=50+2b-3c
14a/14=50/14+2b/14-3c/14
a=50+2b-3c/14
Answer:
Step-by-step explanation:
Amplitude is twice the coefficent of the sine function. In this case, 
Period is
divided by the coefficent of x, in this case, 
Phase shift, is how much you sum or subctract from x inside the sine, in this case
.
Midline you get by hiding the sine and reading what's left, in this case, -4.
I think its figure A but i am not sure.