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SpyIntel [72]
3 years ago
12

3^sqrt -64w^12

qrt[3]{ - 64w^{12}} " alt=" \sqrt[3]{ - 64w^{12}} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Agata [3.3K]3 years ago
7 0
-64=(-4)³, w^12=(w^4)³
the result is -4w^4
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Reptile [31]

Answer:

\frac{49}{28}

Step-by-step explanation:

Evaluate g(- 4) and f(- 4) by substituting x = - 4 into g(x) and f(x), that is

f(- 4) = - 10(- 4) + 9 = 40 + 9 = 49

g(- 4) = (- 4)² + 12 = 16 + 12 = 28

Then

\frac{f(-4)}{g(-4)} = \frac{49}{28} = \frac{7}{4}

7 0
3 years ago
Sarah stands at the corner of a rectangular field. If the field measures 180 m by 210 m, how far would Sarah need to walk to
Agata [3.3K]

Answer:

30√85 or 276.5863 meters

Step-by-step explanation:

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4 0
2 years ago
Prove by mathematical induction that 1+2+3+...+n= n(n+1)/2 please can someone help me with this ASAP. Thanks​
Iteru [2.4K]

Let

P(n):\ 1+2+\ldots+n = \dfrac{n(n+1)}{2}

In order to prove this by induction, we first need to prove the base case, i.e. prove that P(1) is true:

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So, the base case is ok. Now, we need to assume P(n) and prove P(n+1).

P(n+1) states that

P(n+1):\ 1+2+\ldots+n+(n+1) = \dfrac{(n+1)(n+2)}{2}=\dfrac{n^2+3n+2}{2}

Since we're assuming P(n), we can substitute the sum of the first n terms with their expression:

\underbrace{1+2+\ldots+n}_{P(n)}+n+1 = \dfrac{n(n+1)}{2}+n+1=\dfrac{n(n+1)+2n+2}{2}=\dfrac{n^2+3n+2}{2}

Which terminates the proof, since we showed that

P(n+1):\ 1+2+\ldots+n+(n+1) =\dfrac{n^2+3n+2}{2}

as required

4 0
3 years ago
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iVinArrow [24]

Answer:

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8.88

<em><u>If this helped, please consider picking this answer as the Brainliest Answer. Thank you!</u></em>

3 0
2 years ago
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yarga [219]

Answer:

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Step-by-step explanation:

dont know

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