Answer:
28.56/linear yard
32.2256/linear meter
121.77984k
Step-by-step explanation:
a) Scale = k9.52*3 = 28.56/linear yard
b) Scale = k9.52*3.28 = 32.2256/linear meter
c) Cost = 3.9 * 32.2256 = 121.77984k
Step-by-step explanation:
it filled up half the circle (up to the center point) - if we had a full circle. but a little bit is cut off (below AB).
what we see is that the shaded area is the sum of the area of the triangle AOB and 2 equally sized circle segment areas left and right of AOB.
since we are dealing with a half-circle, we have 180° in total. 120° are taken by AOB, so, that leaves us with 180-120 = 60° for both circle segments (so, one has an angle of 30°).
and 2×30° = 1×60°, so we can calculate the area of one 60° segment instead of two 30° segments.
AOB is an isoceles triangle (the legs are equally long, and therefore also the 2 side angles are equal).
the area of this triangle AOB is
1/2 × a × b × sin(C) = 1/2 × 3 × 3 × sin(120) =
= 3.897114317... m²
a circle segment area of 60° is 60/360 = 1/6 of the full circle area (as a full circle = 360°).
so, it's area is
pi×r² × 1/6 = pi×3²/6 = pi×3/2 = 4.71238898... m²
so, the total area of the shaded area is
3.897114317... m² + 4.71238898... m² =
= 8.609503297... m²
Answer:
n<2
Step-by-step explanation:
move all terms not containing n to the right side of the inequality
Answer:
169.1 unit^2 to the nearest tenth.
Step-by-step explanation:
Area of the parallelogram = base * height
= 24 * 6 unit^2.
Area of the semicircle = 1/2 pi r^2.
Here r = 1/2 * 8 = 4.
So the area is 1/2 * pi * 4^2
= 8pi unit^2.
The area of the whole figure = 24*6 + 8pi
= 169.13 unit^2.
