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denis23 [38]
3 years ago
10

Whats an equation for the sum of eight and twice a number is fourteen

Mathematics
2 answers:
kodGreya [7K]3 years ago
6 0
So first lets turn this into equation. 8+(2*n)=14
dexar [7]3 years ago
3 0
The answer is 2x+8=14
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Which expression is equivalent to this expression?<br><br> (-5cd-4)(2cd2)2
GarryVolchara [31]

Answer: If the answer needs to be simplified, then the answer would be

-20c^2 d^3 - 16cd^2

Step-by-step explanation:

8 0
3 years ago
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How to simplify (-12)-7×(-12)7
Strike441 [17]
(-12)1 because of how you break it down
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3 years ago
Assume that the Poisson distribution applies and that the mean number of aircraft accidents is 9 per month. Find​ P(0), the prob
Ugo [173]

Answer: 0.0001

It is unlikely to have a month with no aircraft​ accidents .

Step-by-step explanation:

Given :  Mean number of aircraft accidents = 9 per month

The Poisson distribution formula :-

\dfrac{e^{-\lambda}\lambda^x}{x!}, where \lambda is the mean of the distribution.

If X = the number of aircraft accidents per month, then the probability that in a​ month, there will be no aircraft accidents will be :-

\dfrac{e^{-9}(9)^0}{0!}=0.000123409804087\approx0.0001

Hence, the probability that in a​ month, there will be no aircraft accidents = 0.0001

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5 0
3 years ago
Question 11 (2.5 points)
Rama09 [41]

Answer:

D

Step-by-step explanation:

The answer is d, because a represents adults, and c represent children. It's $45 per adult, so $45a, and $30 per child, so $30c. a+c is equal to 10, because that's how many tickets were purchased. $45a+$30c=345, because $345 is the total amount spent on tickets.

3 0
3 years ago
Sums of a sequence: How many total gifts did my true love give to me during the entire 12 days of Christmas? Hint: Without any o
ale4655 [162]
<span> On the first day of Christmas,
my true love sent to me
A partridge in a pear tree. On the second day of Christmas,
my true love sent to me
Two turtle doves,
And a partridge in a pear tree. On the third day of Christmas,
my true love sent to me
Three French hens,
Two turtle doves,
And a partridge in a pear tree. </span>

The song continues, adding 4 calling birds on the 4th day, 5 golden rings on the 5th, and so on up to the 12th day, when 12 drummers add to the cacophony of assorted birds, pipers and lords leaping all over the place.

Notice that on each day there is one partridge (so I will have 12 partridges by the 12th day), and each day from the second day onwards there are 2 doves (so I will have 22 doves), and from the 3rd there are 3 hens (total of 30 hens), and so on.

So, how many presents are there altogether?

Partridges: 1 × 12 = 12

Doves: 2 × 11 = 22

Hens 3 × 10 = 30

Calling birds: 4 × 9 = 36

Golden rings: 5 × 8 = 40

Geese: 6 × 7 = 42

Swans: 7 × 6 = 42

Maids: 8 × 5 = 40

Ladies: 9 × 4 = 36

Lords: 10 × 3 = 30

Pipers: 11 × 2 = 22

Drummers: 12 × 1 = 12

Total = 364

We observe that we have the same number of partridges as drummers (12 of each); doves and pipers (22 of each); hens and lords (30 of each) and so on. So the easiest way to count our presents is to add up to the middle of the list and then double the result: (12 + 22 + 30 + 36 + 40 + 42) × 2 = 364.


3 0
3 years ago
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