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elena-s [515]
3 years ago
15

A freight train from city A to city B and a passenger train from city B to city A left the cities at the same time, at 10:00 AM,

heading towards each other. The distance between the cities is 360 miles. The freight train is travelling at 50 mph, the passenger train is travelling at 70 mph. At what time will the trains pass each other
Mathematics
1 answer:
djyliett [7]3 years ago
8 0

Answer: Both trains would meet at 1 pm

Step-by-step explanation:

Let t represent the time at which both trains will pass each other.

The distance between the cities is 360 miles. This means that by the time both trains meet, the total distance covered would be 360 miles.

Distance = speed × time

The freight train is travelling at 50 mph. Distance covered by the freight train in t hours is 50t.

The passenger train is travelling at 70 mph. Distance covered by the passenger train in t hours is 70t.

Since the total distance covered is 360 miles, it means that

50t + 70t = 360

120t = 360

t = 360/120

t = 3 hours

Both trains would meet at 1 pm

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The answer would be 6.4
3 0
3 years ago
Find the coordinates of the points of intersection of the graphs with coordinate axes: y=− 1/4 x+2
bearhunter [10]

Answer:


Step-by-step explanation:

Here, you can use a simple formula.

To find the point of intersection you just put x=0 or y=0.

Because, if a graph intersects x-axis, then at this point  y=0

Similarly, if a graph intersects y-axis, then at this point  x=0


So, for our given line.

y=-1/4 x +2

when , x=0 , y=-1/4 (0)+2=2

So, the graph intersects y-axis at   y=2


when , y=0 ,

then    0=-1/4 x+2

       or, 1/4 x=2

       or, x=8    [multiplying by  4]

So, the graph intersects x-axis at   x=8

3 0
3 years ago
5 - (-9 ) subtracting intergers
ruslelena [56]

Answer:

14

Step-by-step explanation:

Hope this will help you....

4 0
3 years ago
Read 2 more answers
Part A
labwork [276]

An <em>algebraic expression</em> is one that consists of both <u>number(s)</u> and an <u>alphabet(s)</u>. The <em>required</em> answers are:

i. Distance from Chenoa's <u>house</u> to the <em>coffee shop</em> = 6.0 miles

ii. D<u>istance</u> from <em>coffee shop</em> to Chenoa's <u>school</u> = 1.5 miles

iii. <em>Distance</em> from Chenoa's <u>house</u> to her <u>school</u> = 7.5 miles

An <em>algebraic expression</em> is one that consists of both <u>number(s)</u> and an <u>alphabet(s)</u>. The <em>alphabet</em> is referred to as the <u>unknown</u> whose <u>value</u> has to be <em>determined</em>.

In the given question, let the <u>distance</u> from the <em>coffee shop</em> to Chenoa's <u>school</u> be represented by y.

So that;

The <u>distance</u> from Chenoa's house to the <em>coffee shop</em> = (2y + 3) miles.

The <em>total distance</em> from Chenoa's <u>house</u> to her <u>school </u>= 5y.

This implies that:

(2y + 3) + y = 5y

3y + 3 = 5y

3 = 5y - 3y

2y = 3

y = \frac{3}{2}

  = 1.5

The <em>distance</em> from the <em>coffee shop</em> to Chenoa's <u>school</u> is 1.5 miles.

Thus;

(2y + 3) = ( 2(1.5) + 3)

            = 6

The <u>distance</u> from Chenoa's <u>house</u> to the <em>coffee shop</em> is 6 miles.

And,

5y = 5(1.5)

    = 7.5

The <em>total distance</em> from Chenoa's <u>house</u> to her <u>school</u> is 7.5 miles.

For more clarifications on algebraic expressions, visit: brainly.com/question/12792264

#SPJ1

5 0
2 years ago
A circle has a radius of 6. An arc in this circle has a central angle of 330
sashaice [31]

Answer: Arc\ lenght\approx34.55\ units

Step-by-step explanation:

<h3> The complete exercise is: " A circle has a radius of 6. An arc in this circle has a central angle of 330 degrees. What is the arc length?"</h3><h3></h3>

To solve this exercise you need to use the following formula to find the Arc lenght:

Arc\ lenght=2\pi r(\frac{C}{360})

Where "C" is the central angle of the arc (in degrees) and "r" is the radius.

In this case, after analize the information given in the exercise, you can identify that the radius and the central angle in degrees, are:

r=6\ units\\\\C=330

Therefore, knowing these values, you can substitute them into the formula:

Arc\ lenght=2\pi (6\ units)(\frac{330}{360})

And finally,you must evaluate in order to find the Arc lenght.

You get that this is:

Arc\ lenght=2\pi (6\ units)(\frac{11}{12})\\\\Arc\ lenght=11\pi \ units\\\\Arc\ lenght\approx34.55\ units

3 0
3 years ago
Read 2 more answers
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