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4 years ago

Please I need help. Don’t understand

Mathematics

1 answer:

Rom4ik [11]4 years ago

8 0

Just plug in the same X values from function Y into function A then compare.

X Y(FunctionA) Y(Function B)
-9 5/3(-9) - 2 = -17 -7
3 5/3(3) - 2 = 3 1
9 5/3(9) - 2 = 13 5

From this, you can see that any number greater than 0 is going to be larger for function A than it is for function B. You can guess that anything bigger than 3 will be larger for A than B.

Therefore, the first statement is true.

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What is the simplified form of the expression 0.3 (4x - 4y)?

Agata [3.3K]

Answer:

1.2x-1.2y

Step-by-step explanation:

8 0

3 years ago

Write an equation of the line that passes through (-1,2) with a slope of 4

Iteru [2.4K]

Step-by-step explanation:

Hey there!

Given;

The points is; (-1 , 2) and slope is 4.

Note: Use one-point formula.

$(y - y1) = m(x - x1)$

~ Put all values.

$(y - 2) = 4(x + 1)$

~ Simplify it.

$(y - 2) = 4x + 4$

$4x - y + 6 = 0$

Therefore, the required equation is; 4x-y+6=0.

<h3>Hope it helps...</h3>

6 0

3 years ago

A line has a slope of 2 and passes through the point (3, 9). Which is the equation of the line?

Oxana [17]

We know, y - y1 = m(x - x1)
y - 9 = 2(x - 3)
y - 9 = 2x - 6
y = 2x + 3

In short, Your Answer would be Option B

Hope this helps!

3 0

3 years ago

What is the answer????

dem82 [27]

E I think I am not sure though.

6 0

3 years ago

Sulfur compounds cause "off-odors" in wine, so winemakers want to know the odor threshold, the lowest concentration of a compoun

aev [14]

Answer:

a) $29.4-1.96\frac{7}{\sqrt{10}}=25.06$

$29.4+1.96\frac{7}{\sqrt{10}}=33.74$

So on this case the 95% confidence interval would be given by (25.06;33.74)

b) $z=\frac{29,4-25}{\frac{7}{\sqrt{10}}}=1.988$

$p_v =P(z>1.988)=0.0234$

If we compare the p value and the significance level given $\alpha=Step-by-step explanation:Previous conceptsA confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval". 
The margin of error is the range of values below and above the sample statistic in a confidence interval. 
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean". 
Part a
Data given: 30 30 42 35 22 33 31 29 19 23
We can calculate the sample mean with the following formula:[tex] \bar X = \frac{\sum_{i=1}^n X_i}{n}= 29.4$ the sample mean

$\mu$ population mean (variable of interest)

$\sigma=7$ represent the population standard deviation

n=10 represent the sample size

95% confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$

Now we have everything in order to replace into formula (1):

$29.4-1.96\frac{7}{\sqrt{10}}=25.06$

$29.4+1.96\frac{7}{\sqrt{10}}=33.74$

So on this case the 95% confidence interval would be given by (25.06;33.74)

Part b

What are H0 and Ha for this study?

Null hypothesis: $\mu \leq 25$

Alternative hypothesis : $\mu>25$

Compute the test statistic

The statistic for this case is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$z=\frac{29,4-25}{\frac{7}{\sqrt{10}}}=1.988$

Give the appropriate conclusion for the test

Since is a one side right tailed test the p value would be:

$p_v =P(z>1.988)=0.0234$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

8 0

3 years ago