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Inessa05 [86]
3 years ago
11

Why Is markup necessary for retail sales

Mathematics
1 answer:
vlabodo [156]3 years ago
8 0
Markup is necessary for the company to gain money instead of losing money
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When a particular mass-spring system is started by stretching the spring 3 cm, one complete oscillation takes 4 seconds.
11Alexandr11 [23.1K]

Answer:

A. 5.16 s.

B. 5.66 s.

Step-by-step explanation:

A.

For a simple harmonic motion,

T = 2pi (sqrt * (l/g))

Given:

L1 = 3 cm

T1 = 4 s

L2 = 5 cm

T2 = ?

4 = 2pi*sqrt(3/g)

g = 7.4

At, L2,

T2 = 2pi*sqrt(5/7.4)

= 5.16 s.

B.

M1 = M1

M2 = 2*M1

For a simple harmonic motion,

T = 2pi (sqrt * (m/k))

4 = 2pi (sqrt * (M1/k))

M1/k = 0.405

Inputting the above values,

T2 = 2pi (sqrt * (2*M1/k))

= 2pi (sqrt * (2 * 0.405))

= 5.66 s.

4 0
3 years ago
A line includes the points (10,-5) and (-10,-1). What is the equation in slope intercept form?
Elodia [21]

\bf (\stackrel{x_1}{10}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{-10}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-(-5)}{-10-10}\implies \cfrac{-1+5}{-20}\implies \cfrac{4}{-20}\implies -\cfrac{1}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-5)=-\cfrac{1}{5}(x-10) \\\\\\ y+5=-\cfrac{1}{5}x+2\implies y=-\cfrac{1}{5}x-3

8 0
3 years ago
20% of 150 what is your number​
adoni [48]

Answer:

20% of 150 is 30 :)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Find the missing endpoint if S is the midpoint RT
Stolb23 [73]

Answer:

  10. T(-20, 9)

  11. R(-1, -9)

  12. D(-6, 5)

Step-by-step explanation:

The relationship between end points and the midpoint can be solved generically for one of the end points. That relation can be used for the different points in these problems.

__

<h3>generic solution</h3>

The coordinates of midpoint M is related to the coordinates of end points A and B by ...

  M = (A +B)/2

This can be solved for end point B, given end point A and midpoint M:

  2M = A +B

  2M -A = B

Then the generic equation for end point B given end point A and midpoint M is ...

  B = 2M -A

__

In each of the numbered problems, the midpoint and one end point are given. These can be matched with the variables in the above formula, so the solution is simply a matter of arithmetic. Beware all the minus signs.

<h3>10.</h3>

  T = 2R -S

  T = 2(-9, 4) -(2, -1) = (2(-9) -2, 2(4) +1)

  T = (-20, 9)

__

<h3>11.</h3>

  R = 2S -T

  R = 2(-4, -6) -(-7, -3) = (2(-4) +7, 2(-6) +3)

  R = (-1, -9)

__

<h3>12.</h3>

  B = (A +C)/2 = ((-9, -4) +(-1, 6))/2 = (-9 -1, -4 +6)/2 = (-10, 2)/2

  B = (-5, 1) . . . . the missing midpoint of AC

  D = 2B -E . . . . the missing end point of BD

  D = 2(-5, 1) -(-4, -3) = (2(-5) +4, 2(1) +3)) = (-10 +4, 2 +3)

  D = (-6, 5)

8 0
2 years ago
Find the coordinates of the other endpoint of the<br> midpoint (-6,23), endpoint (-4.19)
choli [55]

Answer:

(-8 , 27)

Step-by-step explanation:

(-6,23)= (x ,y )\\\\(-4 ,19)=(x_1,y_1)\\\\x = \frac{x_1+x_2}{2}\\ \\-6 = \frac{-4+x_2}{2}\\ \\-12 =-4+x_2\\\\-12+4 =x_2\\-8=x_2\\\\y = \frac{y_1+y_2}{2}\\ \\23 = \frac{19+y_2}{2} \\\\46 =19+y_2\\\\46-19=y_2\\27=y_2

7 0
3 years ago
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