Using it's concept, the average rate of change of the function over the interval 10 < x < 22 is given by:
<h3>What is the average rate of change of a function over an interval?</h3>
It is given by the change in the <u>output divided by the change in input</u>.
Over the interval 10 < x < 22, the outputs are f(10) and f(22), hence the rate of change is given by:
More can be learned about the average rate of change of a function at brainly.com/question/24313700
#SPJ1
Volume of Sphere = (4/3)*(pi)*(r^3)
r = (D/2) = 6 m
=<span>(4/3)*(pi)*((6^3)
= 904.7786.. m^3
I hope this helps.</span>
2(7÷10)×1÷3+4÷15=1.4×0.33+0.267
=0.462+0.267
=0.729(0.73)
Hola User_______________
Here IS YOUR Answer...!!!
_______________________
A.) 5.) 2/3 × 2/3 × 2/3 = (2/3)^3
6.) 4 × 4 × 4 = (4)^3
B.) 8.) (0.25) × (0.25) × (0.25)
9.) (1/9)×(1/9)×(1/9)
C.)
11.)3^3 = 9 and 4^3 = 64
12.)(4)^6 miles = 4096 miles
Answer:
x=2 (-7 , then -5 for the drag part)
