PLS HURRY<br> Use the protector to measure the angle.

Complete this activity. Interest at the rates of 5%, 6%, and 8% is earned on investments of $13,000, $12,000, and $4,000 respect

zvonat [6]

The answer is 1690. First find the amount of interest by a single investment by multiplying the investment amount by the percent interest in decimal form. Then calculate the total by adding up all the products of investment times interest. Matrices will allow to multiply two things together and add the products up all at the same time. So we need to find the investment matrix and interest matrix.

Investment matrix A (transposed) = (a1 a2 a3) = (13,000 12,000 4,000)

Interest Matrix B = (b1 b2 b3) = (0.05 0.06 0.08)

Amount of interest earned = a1b1 + a2b2 + a3b3

Amount of interest earned = (0.05) (13,000) + (0.06) (12,000) + (0.08)(4,000)

Amount of interest earned = 1690

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3 years ago

A buyer went to the market to buy strawberries. He purchased 120 randomly selected strawberries from a vendor who claimed that n

mafiozo [28]

Answer:

$z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10$

$p_v =P(z>2.10)=0.018$

At 5% of significance we can conclude that the true proportion of strawberries damage is higher than 0.25

Step-by-step explanation:

Data given and notation

n=120 represent the random sample taken

X=40 represent the number of strawberries damaged

$\hat p=\frac{40}{120}=0.333$ estimated proportion of strawberries damaged

$p_o=0.25$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that no more than 25% of his total harvest of strawberries was damaged.:

Null hypothesis: $p\leq 0.25$

Alternative hypothesis: $p > 0.25$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>2.10)=0.018$

At 5% of significance we can conclude that the true proportion of strawberries damage is higher than 0.25

6 0

2 years ago

Okay here are more math problems.

Vinil7 [7]

Answer:

the inequality would be, b/3<=16

Step-by-step explanation:

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