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neonofarm [45]
3 years ago
7

Point N is on line segment MO. Given NO = 2x – 3, MO = 3x + 5, and

Chemistry
1 answer:
Zigmanuir [339]3 years ago
5 0

Answer:

MO = 20

Explanation:

Given that: MO = 3x + 5

                  MN = 2x + 3

                  NO = 2x - 3

But,

MO = MN + NO

So that;

3x + 5 = (2x + 3) + (2x - 3)

3x + 5 = 2x + 3 + 2x - 3

3x + 5 = 4x

3x - 4x = -5

-x = -5

Multiply through by minus,

x = 5

Thus,

MO = 3x + 5

      = 3(5) + 5

      = 15 + 5

MO = 20

The length of MO is 20.

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Science / Chemistry Worksheet
kaheart [24]

Explanation:

K2O Now the cation is the element at the front so it would be K2 because the 2 belongs with the K which is Potassium and now Anion is the last element O for oxygen

7 0
4 years ago
A 0.250 g sample of hydrocarbon (containing only carbon and hydrogen) undergoes complete combustion to produce 0.845 g of CO2 an
melomori [17]

Answer:

CH

Explanation:

We have to obtain the mass of carbon and hydrogen in CO2 and H2O respectively.

For carbon in CO2;

0.845 * 12/44 = 0.23 g

For hydrogen in H20;

0.173 * 2/18 = 0.019 g

We convert the masses to moles of carbon and hydrogen

For carbon - 0.23/ 12 = 0.019 moles

For hydrogen - 0.019/1 = 0.019 moles

Dividing by 0.019 moles for carbon and hydrogen we have the emperical formula of the compound as CH

5 0
3 years ago
What is the mass grams that are in 2.57 × 10²⁵ molecules of I₂
lina2011 [118]

The mass of I₂ that contains 2.57×10²⁵ molecules is 10843.52 g

From a detailed understanding of Avogadro's hypothesis, we understood 1 mole of any substance contains 6.02×10²³ molecules. This implies that 1 mole of I₂ also 6.02×10²³ molecules i.e

<h3>6.02×10²³ molecules = 1 mole of I₂</h3>

Recall:

1 mole of I₂ = 2 × 127 = 254 g

Thus,

<h3>6.02×10²³ molecules = 254 g of I₂</h3>

With the above information, we can obtain the mass of I₂ that contains 2.57×10²⁵ molecules. This is illustrated below:

6.02×10²³ molecules = 254 g of I₂

Therefore,

2.57×10²⁵ molecules = \frac{2.57*10^{25}  * 254}{6.02*10^{23}}\\\\

<h3>2.57×10²⁵ molecules = 10843.52 g of I₂</h3>

Thus, the mass of I₂ that contains 2.57×10²⁵ molecules is 10843.52 g

Learn more: brainly.com/question/24848191

5 0
2 years ago
Aqueous sulfuric acid will react with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . Suppose 2.9 g
garri49 [273]

Answer:

1.07 g of water.

Explanation:

A reaction between an acid and a base makes water and a salt as product.

Our reaction is:

H₂SO₄ +  2NaOH  →  Na₂SO₄  +  2H₂O

Reactants are the acid and the base. Which is the limiting?

2.9 g . 1mol /98 g =  0.0296 moles of acid

3.53 g . 1mol / 40 g = 0.088 moles of base

2 moles of base react to 1 mol of acid

0.088 moles may react to (0.088 . 1)/2 = 0.044 moles of acid

And we only have 0.0296, sulfuric acid is the limiting

Ratio is 1:2. 1 mol of acid can produce 2 moles of water.

Our 0.0296 moles may produce (0.0296 . 2) /1 = 0.0592 moles of water.

We convert moles to mass:

0.0592 mol . 18g /mol = 1.07 g

6 0
3 years ago
At 20 ∘C the vapor pressure of benzene C6H6 is 75 torr and that of toluene C7H8 is 22 torr. Assume that benzene and toluene fo
Olegator [25]

Answer:

a) Xbenzene = 0.283

b) Xtoluene = 0.717

Explanation:

At T = 20°C:

⇒ vapor pressure of benzene (P*b) = 75 torr

⇒ vapor pressure toluene (P*t) = 22 torr

Raoult's law:

  • Pi = Xi.P*i

∴ Pi: partial pressure of i

∴ Xi: mole fraction

∴ P*i: vapor pressure at T

a) solution: benzene (b) + toluene (t)

∴ Psln = 37 torr;   at T=20°C

⇒ Psln = Pb + Pt

∴ Pb = (Xb)*(P*b)

∴ Pt = (Xt)*(P*t)

∴ Xb + Xt = 1

⇒ Psln = 37 torr = (Xb)(75 torr) + (1 - Xb)(22 torr)

⇒ 37 torr - 22 torr = (75 torr)Xb - (22 torr)Xb

⇒ 15 torr = 53 torrXb

⇒ Xb = 15 torr / 53 torr

⇒ Xb = 0.283

b) Xb + Xt = 1

⇒ Xt = 1 - Xb

⇒ Xt = 1 - 0.283

⇒ Xt = 0.717

6 0
4 years ago
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