Answer:
He discovered neutrons in 1932
Anthracene is a polycyclic aromatic hydrocarbon with chemical formula C₁₄H₁₀. The number of fused rings in Anthracene are three in number. This compound is colorful and is used in the formation of different dyes due to its property of deloclization of pi electrons. All the carbon atoms in Anthracene are sp² hybridized with a trigonal planar structure hence, the Anthracene is planar in nature.
Number of Sigma Bonds:
There are 26 sigma bonds (colored in Blue) in Anthracene among which 10 sigma bonds are between carbon and hydrogen atoms while the remaining are between the carbon atoms.
Number of Pi-Bonds:
There are 7 pi bonds in Anthracene (colored in red). All pi bonds are present between carbon and carbon atoms.
Number of Electrons in Sigma Bonds:
As one sigma bond is formed by 2 electrons hence, 26 sigma bonds will be formed by 52 electrons.
Number of Electrons in Pi Bonds:
As one pi bond is formed by the side wise overlap of two p orbitals hence one pi bond is formed by two electrons so, 7 pi bonds will be formed by 14 electrons.
Answer:
C. radioactive material
Explanation:
This exposure primarily comes from cosmic rays, radioactive material in the earth (such as uranium-238), ingestion of naturally occurring radionuclides in food (such as potassium- 40), and inhalation of radon gas. In the United States, the average background radiation dose is 300 mrem/yr.
The correct student would be student D since an ionic bond is made up of a metal and nonmetal where metals usually give electrons and nonmetals take.
number of moles of HI = 1.7 mol
number of moles of ZnBr2 = 3.43 mol
2HI + ZnBr2 → 2HBr + ZnI2
every 2 mole of HI will require 1 mole of ZnBr2
mole of ZnBr2 that will react = 1.7 / 2 = 0.85 mol
Therefore HI is the limiting reactant and not all ZnBr2 will be reacted
For every 2 mole of HI will form one mole ZnI2
1.7/2 = 0.85 mol of ZnI2 formed