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Nonamiya [84]
3 years ago
7

I need help with number 5 please??

Chemistry
1 answer:
AlladinOne [14]3 years ago
8 0
It is a easy one. Keep working and don't stress about it, you'll see, doing this problem alone will securise you
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How would I complete this table?
defon

Answer:

Fist column, apply the density of water.

Second column is material density, so it's mass of sample / volume of sample

Explanation:

Water density is 1 g/mL

Mass / Volume

If you have 0.25 g, 0.45g and 0.46 g of water, then you have the same values as volume,  0.25mL, 0.45mL and 0.46mL.

Again, density is the relation mass / volume so:

2.20 g / 0.25mL

3.73 g / 0.46 mL

3.52 g / 0.45mL

4 0
3 years ago
What class of organic molecule is shown below?но|||OA. Carboxylic acidOB. AldehydeOC. EsterOD. KetoneH-C-C-O-C-C-HHHIIHHH
Lady bird [3.3K]

So,

The most important functional organic groups are shown in the following picture:

If we analyze your molecule properly, we can identify the following:

The answer is Ester.

5 0
2 years ago
Alexa has a sample of gold that has a density of 19.32g/cm. She measured its mass to be
JulijaS [17]

Answer:

The volume of gold is 3.3 cm³.

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m³.

Other units are given below,

g/cm³, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given data:

Mass of gold = 63 g

Density of gold = 19.32 g/cm³

Volume of gold = ?

Solution:

d = m/v

v = m/d

v = 63 g/ 19.32 g/cm³

v = 3.3 cm³.

8 0
3 years ago
What do these two changes have in common?
Arada [10]

Answer: Both are only physical changes. •

Explanation:

8 0
2 years ago
sebanyak 36 gram glukosa (C6H12O6,M=180 g/mol) dilarutkan dalam 250 gram air.jika diketahui Kb air= 0,52° kg/mol.tentukan titik
likoan [24]
Gr terlarut = 36 gr 
<span>Mr terlarut = 180 </span>
<span>gr pelarut = 250 gr </span>
<span>Kb air = 0,52 °C kg/mol </span>

<span>Tb larutan = ........? </span>
<span>--------------------------------------... </span>
<span>ΔTb = Kb.m.i </span>
<span>ΔTb = Kb. (gr t / Mr t) . (1000/ gr p) .i </span>
<span>ΔTb = 0,52 x (36/180) x (1000/250) x 1 </span>
<span>ΔTb = 0,416 °C </span>

<span>Tb = 100 + ΔTb </span>
<span>Tb = 100 + 0,416 </span>
<span>Tb = 100,416 °C</span>
4 0
3 years ago
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