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Vlad [161]
3 years ago
5

Find the volume occupied by 4.00 g of helium gas at 25.0o C and 1.18 atm of pressure.

Chemistry
1 answer:
Triss [41]3 years ago
6 0

Answer: 41.46 L

Explanation:

La ecuación que describe  relación entre presión, volumen,  temperatura y la cantidad (en moles)

de un gas ideal es:   PV = nRT

Donde:  P = Presión absoluta ,  V= Volumen  , n = Moles de gas , R = Constante universal de los gases ideales,  T = Temperatura absoluta,

R = 0.082 L. atm/mol. °K

V = nRT/P

Calculanting n

n = mass/ molecular mass

<h3>n = 4 g / 2g. mol⁻¹</h3><h3>n = 2 mol</h3><h3>T =25⁰ + 273 ⁰K = 298 ⁰K</h3><h3>V = (2 mol ₓ0.082 L. atm / mol.°K x 298 ⁰K) / 1.18 atm = 41.46 L</h3>
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In-s [12.5K]

Answer:

Sorry

Explanation:

Sorry this is not chemistry but I always try to answer but this time I can't I am so so sorry

4 0
3 years ago
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ELEN [110]

Answer:

c

Explanation:

6 0
3 years ago
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The concentration of hydroxide ions is greater than the concentration of hydronium ions for acidic solutions.
Katena32 [7]

Answer:

True

Explanation:

It's true because the pH is a measure of how basic or acid a solution is. In an acidic medium, the pH scales goes from 0 to 7. While in a basic medium goes from 7 to 14. The lower the pH value of the most acid the solution is.

1. The expression pH = -log(molar concentration of hydronium) allow to calculate the pH of a solution.

2. On the other hand, the expression pOH = -log(molar concentration of hydroxide) allow to determine the pOH of a solution.

The values of pH and pOH always obey the following expression:

pH + pOH = 14

Thus if for instance the pH becomes smaller the pOH must become bigger in order to fulfill the equation. Which means that the concentration of hydronium ions is greater than the hydroxide concentration.

For example, in an acidic medium:

if pH= 3, pOH= 11

In this case the molar concentration of hydronium is 0,001M. And the molar concentration of hydroxide ions is just 0,00000000001M.

6 0
4 years ago
Read 2 more answers
How many parts per million of fluoride in a solution that is 500 grams of fluoride and 500,000 liters water
erik [133]

0.000001‬ppm

Explanation:

Mass of fluoride = 500g

Volume of water = 500000liters

Unknown:

Parts per million of fluoride = ?

Solution:

The parts per million is the amount of solute in milligram dissolved in a liter of water or milligram per kilogram of solvent

It is a unit used to express very small concentration.

 we need to convert g - mg

   500g = 500 x  10⁻³mg  = 0.5mg

   Concentration in parts per million = \frac{mass in mg}{Volume in liters}

Concentration in parts per million = \frac{0.5}{500000} = 0.000001‬ppm

learn more:

Parts per million brainly.com/question/2854033

#learnwithBrainly

7 0
4 years ago
What is the mass of 1.58 moles of CH4
HACTEHA [7]
<h3>Answer:</h3>

25.4 g CH₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.58 mol CH₄

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of C - 12.01 g/mol

[PT] Molar Mass of H - 1.01 g/mol

Molar Mass of CH₄ - 12.01 + 4(1.01) = 16.05 g/mol

<u>Step 3: Convert</u>

  1. Set up:                               \displaystyle 1.58 \ mol \ CH_4(\frac{16.05 \ g \ CH_4}{1 \ mol \ CH_4})
  2. Multiply/Divide:                 \displaystyle 25.359 \ g \ CH_4

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

25.359 g CH₄ ≈ 25.4 g CH₄

4 0
3 years ago
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