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raketka [301]
4 years ago
6

If I have 27L of a 0.003 M solution of salt water, how many molecules of salt do I have?​

Chemistry
1 answer:
creativ13 [48]4 years ago
6 0

Answer:

no. of molecules of salt =  5.046 x 10²²

Explanation:

Data given:

Volume of the Solution = 27 L

Molarity of the Solution = 0.003

Number of molecules of salt = ?

Solution:

First find number of moles of salt

Formula used

                      Molarity = moles of solute / L of solution

Rearrange the above equation

                      moles of solute = Molarity x L of Solution

Put values in above equation

                    moles of solute = 0.003 x 27 L

                    moles of solute = 0.081 moles

Now we can find the number of molecules of salt

Formula used to find no. of molecules

      no. of moles = no. of molecules / Avogadro's number

Avogadro's number = 6.23 x 10²³

Now rearrange the above equation

     no. of molecules = no. of moles x Avogadro's number . . . . . . . (1)

Put values in Equation 1

      no. of molecules =  0.081 moles x 6.23 x 10²³

      no. of molecules =  5.046 x 10²²

So,

no. of molecules of salt =  5.046 x 10²²

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In a chemical reaction how does the mass of the reactants compare with the mass of the products?
Juli2301 [7.4K]

Answer:

The mass of the reactants compared with the mass of the products should be the same if the reactants are in stoichiometric amounts.

Explanation:

In this question, they ask about chemical reactions and the comparison of the mass of reactants and products. Firstly, it is necessary to introduce the mass conservation principle.

Mass conservation principle mentions that in a chemical reaction, the total mass of reactants is equal to the total mass of products (if the reaction is fully developed). It means mass is not created or destroyed, only transforms from reactants to products.

For example, the mass of sodium plus the mass of chlorine that reactswith the sodium equals the mass of the product sodium chloride.Because atoms are only rearranged in a chemical reaction, there mustbe the same number of sodium atoms and chlorine atoms in both thereactants and products.

Finally, we can conclude that The mass of the reactants compared with the mass of the products should be the same if the reactants are in stoichiometric amounts. 

6 0
3 years ago
2. Calculate the density of a metal that occupies 17.75 cm and has a mass of 342.93 g. [D = m/V]
satela [25.4K]

Answer:

19.32

Explanation:

the density is given by the mass over volume

the mass In this case is 342.93 and the volume is 17.75

d=342.93g/17.75cm

=19.32g/cm

i hope this helps

3 0
3 years ago
What is the minimum of acetic anhydride (102.1 g/mol) required to react completely with the 2.94 grams of salicylic acid? What v
Lady bird [3.3K]

Answer:

a) the minimun of acetic anhydride required for the  reaction is 2.175 g (CH3CO)2O

b) V acetic anhydride = 2.010 mL

Explanation:

  • balanced reaction:

      C6H4OHCOOH + (CH3CO)2O  ↔  C9H8O4 + C2H4O2

⇒ mol salicylic acid = 2.94 g C6H4OHCOOH * ( mol C6H4OHCOOH / 138.121 g ) = 0.0213 mol C6H4OHCOOH

⇒ mol acetic anhydride = 0.0213 mol C6H4OHCOOH * ( mol (CH3CO)2O /  mol  C6H4OHCOOH ) = 0.0213 mol (CHECO)2O

⇒ g acetic anhydride = 0.0213 mol * ( 102.1 g/mol ) = 2.175 g CH3CO)2O

b) V = 2.175 g (CH3CO)2 * ( mL / 1.082 g ) = 2.010 mL (CH3CO)2O

4 0
3 years ago
Given that you started with 28.5 g of K3PO4, how many grams of KNO3 can be<br> produced?
Irina18 [472]

Mass of KNO₃ : = 40.643 g

<h3>Further explanation</h3>

Given

28.5 g of K₃PO₄

Required

Mass of KNO₃

Solution

Reaction(Balanced equation) :

2K₃PO₄ + 3 Ca(NO₃)₂ = Ca₃(PO₄)₂ + 6 KNO₃

mol K₃PO₄(MW=212,27 g/mol) :

= mass : MW

= 28.5 : 212,27 g/mol

= 0.134

Mol ratio of K₃PO₄ : KNO₃ = 2 : 6, so mol KNO₃ :

= 6/2 x mol K₃PO₄

= 6/2 x 0.134

= 0.402

Mass of KNO₃ :

= mol x MW KNO₃

= 0.402 x 101,1032 g/mol

= 40.643 g

8 0
3 years ago
The reaction between sodium and oxygen ( balanced with words)
irina1246 [14]
There will be chemical reaction(equation4Na+02--2Na20
3 0
4 years ago
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